Question

4. 12^2x-1 = (V 12)^x

Answer 1

Answer:

Step-by-step explanation:

$12^{2x-1}=(\sqrt[4]{12})^{x}\\\\ 12^{2x-1}= (12^{\frac{1}{4}})^{x}\\\\12^{2x-1}=12^{\frac{1}{4}*x}$

Bases are same. So, compare the exponents.

$2x - 1 =\dfrac{1}{4}x$

Multiply the entire equation by 4

4*(2x - 1) = x

8x - 4 = x

8x     = x + 4

8x -x  = 4

        7x = 4

         x = 4/7