What equation is graphed in this figure? A- y−4=−23(x+2) B-y+2=−32(x−2) C-y−3=32(x+1) D- y+1=−23(x−3)
2 answers:
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<h3>Answer:</h3>
See the attached
<h3>Step-by-step explanation:</h3>When you square the binomial (a -b), you get ...
... (a -b)² = a² -2ab +b²
That is, both the a² and b² terms have positive signs, and the middle term is twice the product of the roots of the squared terms.
The last two selections have negative signs on the constant, so cannot be perfect square trinomials.
The first selection has a middle term that is -ab, not -2ab, so it is not a perfect square trinomial, either.
The second selection is the correct one:
... 4a² -20a +25 = (2a +5)²
2 + 2m = 6 equals m = 2.
First, subtract 2 from both sides. Your problem should look like: 2m = 6 - 2.
Second, simplify 6 - 2 to get 4. Your problem should look like: 2m = 4.
Third, divide both sides by 2. Your problem should look like: m =
Fourth, simplify to 2. Your problem should look like: m = 2, which is the answer.
First, subtract 2 from both sides. Your problem should look like: 2m = 6 - 2.
Second, simplify 6 - 2 to get 4. Your problem should look like: 2m = 4.
Third, divide both sides by 2. Your problem should look like: m =
Fourth, simplify
Here is my table of points:
