All categories

3 years ago

Another question i need help with

Mathematics

1 answer:

Phantasy [73]3 years ago

3 0

Answer:

Step-by-step explanation:

75 is supplementary to angle b. then angle a = 180-75=105

You might be interested in

Find the sum.<br>(w - 2.4) + (1 - 0.5w)

vodka [1.7K]

The sum of the given expression { (w - 2.4) + (1 - 0.5w) } is 0.5w - 1.4.

<h3>What is the sum of the given expression?</h3>

Given the expression in the question;

(w - 2.4) + (1 - 0.5w)

Remove the parenthesis

w - 2.4 + 1 - 0.5w

Collect like terms and simplify

w - 2.4 + 1 - 0.5w

w - 0.5w - 2.4 + 1

1w - 0.5w - 2.4 + 1

0.5w - 1.4

Therefore, the sum of the given expression { (w - 2.4) + (1 - 0.5w) } is 0.5w - 1.4.

Learn more algebra Problems here; brainly.com/question/723406

#SPJ1

8 0

2 years ago

PQR is a straight line.

Strike441 [17]

PQR=PQ+QR

QR=1 unit

PQ=6 units

PQR=7 units

=98cm

7 units----->98cm

1 unit------>98÷7

=14cm

6 units----->14×6

=84cm

4 0

3 years ago

For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

Anni [7]

Answer:

The reduced row-echelon form of the linear system is $\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rows
Multiply one row by a nonzero number
Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

$\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]$

You need to follow these steps:

Divide row 1 by 2 $\left(R_1=\frac{R_1}{2}\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]$

Subtract row 1 from row 2 $\left(R_2=R_2-R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]$

Subtract row 1 multiplied by 5 from row 3 $\left(R_3=R_3-\left(5\right)R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 1 $\left(R_1=R_1-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 3 $\left(R_3=R_3-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]$

Multiply row 2 by 2 $\left(R_2=\left(2\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]$

Divide row 3 by −19 $\left(R_3=\frac{R_3}{-19}\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]$

Subtract row 3 multiplied by 16 from row 1 $\left(R_1=R_1-\left(16\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]$

Add row 3 multiplied by 6 to row 2 $\left(R_2=R_2+\left(6\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

8 0

3 years ago

In a building there are 14 pillars. The radius of each pillar is 21 cm and height 3.5 m. Find the cost

tester [92]

Answer:

I don't know well I didn't got the answer sorry I tried my best

3 0

3 years ago

What is 11/12 closet to

frozen [14]

Answer:

Do you need a decimal? What are you looking for?

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers