Answer:
20 ( B )
Explanation:
Given data:
a and b are 10 map units apart
b and c are 20 map units apart
a and c = 30 map units apart
<em>condition </em>; Triple heterozygote testcrossed
number of progeny = 1000
<u>Determine the number of double crossover result </u>
P( crossover between a and b ) = 10/100 = 0.1
P( crossover between b and c ) = 20/100 = 0.2
p( double crossover ) = 0.1 * 0.2 = 0.02
hence number of double crossovers = number of progeny * 0.02
= 1000 * 0.02 = 20
I believe it is A (Adenine)
Answer:
C. Nucleotides
Explanation:
Nucleic acids are macromolecules which are polymers of nucleotides. There are two types of nucleic acids namely: deoxyribonucleic acid (DNA) and ribonucleic acid (RNA). Nucleotides are the building blocks of nucleic acids.
A nucleotide is made up of three components:
- A phosphate group
- A five carbon sugar called pentose sugar. In RNA the sugar is ribose sugar and in DNA the sugar is deoxyribose sugar.
- Nitrogenous bases: There are four different types of bases in DNA: adenine, guanine, cytosine and thymine. In RNA thymine is replaced by uracil. Adenine and guanine are purines whereas cytosine, thymine and uracil are pyrimidines.
Nitrogenous base and sugar together are called nucleoside and when phosphate is also attached then it is called nucleotide.
It’s what the plant uses to produce food for itself.
Answer:
0%
Explanation:
This question involves a gene coding for height in pea plants. The allele for tallness (T) is dominant over the allele for shortness (t). This means that allele T will be expressed over allele t in an heterozygous state.
A purebred tall plant will possess genotype: TT while a heterozygous tall plant will possess genotype: Tt. The two parents will produce the following gametes:
TT- T and T
Tt- T and t
Using these gametes in a punnet square (see attached image), the following offsprings with genotypes: TT and Tt in a ratio 1:1 will be produced.
TT offsprings are purebreed tall while Tt offsprings are heterozygous tall. Hence, based on the question, no offsprings of this cross will possess the recessive genotype (tt). This means that 0% of the offsprings of this cross will be short.
