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2 years ago

12

The length of a rectangle is five times its width.

1 answer:

cestrela7 [59]2 years ago

7 0

Width is 7 and length is 35
First you set your equation to equal 84 since that’s the total for perimeter is 84. Then you would let the length be 5x since the length is five times the width, that would leave your width to be x. Then you would do x+x+5x+5x=84 then combine like terms. So then it would be 12x=84 divide by 12 which equals x=7 then you plug that in for x which would create the answers of 7 and 35.

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4<br> Which of the following is NOT a possible value of x?<br> 3 A4<br> B 5<br> C 11<br> D 14

Roman55 [17]

I think it’s c for this question

8 0

3 years ago

Mumbi is approximately 845 kilometers away from Bangalore, and Mumbai is approximately 1160 km away from Delhi. The distances, m

Mazyrski [523]

Mumbi is approximately 845 kilometers away from Bangalore, and Mumbai is approximately 1160 km away from Delhi, then the ratio between these distances is

$\dfrac{845}{1160}=\dfrac{169}{232}.$

A. Bangalore to Mumbai: 116.5 cm;

Mumbai to Delhi: 174 cm

The ratio:

$\dfrac{116.5}{174}=\dfrac{233}{348}\neq \dfrac{169}{232}$

This option is false.

B. Bangalore to Mumbai: 42.25

Mumbai to Delhi: 58 cm

The ratio is

$\dfrac{42.25}{58}=\dfrac{845}{1160}=\dfrac{169}{232}$

This option is true.

C. Bangalore to Mumbai: 23.4 cm

Mumbai to Delhi: 29 cm

The ratio is

$\dfrac{23.4}{29}=\dfrac{117}{145}\neq \dfrac{169}{232}$

This option is false.

D. Bangalore to Mumbai: 16.9 cm

Mumbai to Delhi: 23.2 cm

The ratio is

$\dfrac{16.9}{23.2}=\dfrac{169}{232}$

This option is true.

E. Bangalore to Mumbai: 25.35 cm

Mumbai to Delhi: 34.8cm

The ratio is

$\dfrac{25.35}{34.8}=\dfrac{507}{696}=\dfrac{169}{232}$

This option is true.

Answer: correct options are B, D and E

8 0

3 years ago

Read 2 more answers

What is the area of the triangle?<br> 24<br> 10<br> 26<br> units 2 HELP PLEASE

fgiga [73]

A=1/2x Base x Height

= 1/2 (10)(24)

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3 years ago

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Rasek [7]

Answer:

Step-by-step explanation:

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3 years ago

Solve the system algebraically.

Alexandra [31]

Answer:

Let 2x + y - 10 = 0 be equation (a).

Let x - y - 5 = 0 be equation (b).

Make y the subject in equation (b):

${ \tt{x - y - 5 = 0}} \\ { \tt{y = x - 5}}$

Substitute for y in equation (a):

${ \tt{2x + (x - 5) - 10 = 0}} \\ { \tt{3x - 15 = 0}} \\ { \tt{3x = 15}} \\ { \tt{x = 5}}$

Find y in any equation of your choice:

${ \tt{y = (5) - 5}} \\ y = 0$

5 0

3 years ago

Read 2 more answers