Answer:
no u can gain back the a
Step-by-step explanation:
You are not giving much information so the assumption is the base is 2 = meters and the height is 3 meters.<span>
Find total area of a regular pyramid with base of 2 and altitude of 3
</span>
Surface Area = 16.64911 m²
Answer:
The correct option is
Option d. Sin θ = -√65/9 and Tan θ = -√65/4
Step-by-step explanation:
Points to remeber
Sin θ = Opposit side/ Hypotenuse
Cos θ = Adjacent side/Hypotenuse
Tan θ= Opposite side /Adjacent side
<u>To find opposite side</u>
It is given that,
Cos θ = -4/9 = Adjacent side/Hypotenuse
We can find opposite side of angle θ
opposit side ² = Hypotenuse² - adjacent side² = 9² - 4²
= 81 - 16 = 65
Opposite side = √65
<u>To find sinθ and tanθ</u>
Sin θ = Opposit side/ Hypotenuse = -√65/9
Tan θ = Opposite side /Adjacent side = -√65/4
Therefore the correct option is
Option d. Sin θ = -√65/9 and Tan θ = -√65/4
<u />
W=2L-5
-------------
A=L*W
=L(2L-5)
=2L²-5L
-------------
dA/dL=4L-5
When dA/dL=0,
4L-5=0
4L=5
L=5/4
----------------
When L=5/4
A=5/4*(2*(5/4)-5)
=5/4*(10/4-20/4)
=5/4*((-10)/4)
=5/4*(-5/2)
=-25/8
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*You may have been given a badly written out question. The answer doesn't make sense.
Try them and see.
For the first:
3(-3) + 0 = -9 . . . . not > -8
3(-2) + (-1) = -7 . . . is > -8 . . . . . 2) (-2, -1) is a solution
For the second:
4 - 4(-2) = 12 . . . . not ≤ -6
-2 -4(1) = -6 . . . . . is ≤ -6 . . . . . . 2. (1, -2) is a solution