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murzikaleks [220]
2 years ago
8

I need help with this

Mathematics
1 answer:
SSSSS [86.1K]2 years ago
4 0

Answer:

  -26

Step-by-step explanation:

Use the given formula to find the next terms.

  c(1) = 6 . . . . . . given

  c(2) = c(1) -16 = 6 -16 = -10

  c(3) = c(2) -16 = -10 -16 = -26

The third term in the sequence is -26.

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A contractor combined x tons of a gravel mixture that contained 10 percent gravel G, by weight, with y tons of a mixture that co
White raven [17]

Answer:

The value of x would be \frac{3}{5}y or \frac{3}{8}z

Step-by-step explanation:

Given,

x tons of 10% gravel G mixture is mixed with y ton of 2% gravel G to obtain  5% gravel mixture,

Thus, gravel G in x ton + gravel in y ton = gravel G in the resultant mixture,          

⇒ 0.1x + 0.02y = 0.05(x+y),

0.1x - 0.05x = 0.05y - 0.02y

0.05x = 0.03y

\implies x = \frac{0.03}{0.05}y=\frac{3}{5}y----(1)

Now, resultant mixture is z ton,

i.e. z=x+y

\implies y = z - x

From equation (1),

x=\frac{3}{5}(z-x) = \frac{3}{5}z-\frac{3}{5}x

x+\frac{3}{5}x=\frac{3}{5}z

\frac{8}{5}x=\frac{3}{5}z

x=\frac{3}{8}z

3 0
3 years ago
12. When 64 is divided by x, the quotient is a negative
sergey [27]
J. -8 is the correct answer
8 0
3 years ago
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =
geniusboy [140]

The Lagrangian,

L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)

has critical points where its partial derivatives vanish:

L_x=1-\lambda-2\mu x=0

L_y=2+\lambda-2\mu y=0

L_z=9-\lambda=0

L_\lambda=x-y+z-1=0

L_\mu=x^2+y^2-1=0

L_z=0 tells us \lambda=9, so that

L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu

L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}

Then with L_\mu=0, we get

x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2

and L_\lambda=0 tells us

x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}

Then there are two critical points, \left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right). The critical point with the negative x-coordinates gives the maximum value, 9+\sqrt{185}.

8 0
4 years ago
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Mnenie [13.5K]

Answer:

26.4

31.2

33.3

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Write this in equation form 5 less than risk equal to 16
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Risk - 5 = 16. It is just mathematical language.
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