A x b = 400<br> a ÷ b = 4<br>how much is b

Write the equatoin of a graph that has Roots of x={-2,0,4} and has a point of (-1,10)

zheka24 [161]

Step-by-step explanation:

to have "roots" means that the function delivers 0 as function result for these values of x.

so,

f(x) = 0 for x = -2, x = 0 and x = 4

we can build this function as a product of factors.

each factor is an expression of x that turns 0 for the given value of x.

what is the simplest expression of x that turns 0, when x = -2 ?

well : x + 2

as you can easily see, this is 0, when x = -2.

and the easiest existing of x that is 0, when x = 0 ?

totally simple : just x.

and then x - 4 for x = 4

so, our function is

f(x) = x(x + 2)(x - 4)

but : this is one of infinite possibilities.

let's see what happens, if we use the x coordinate (-1) of the given point (-1, 10).

we know, the result must be 10.

-1×(-1 + 2)(-1 - 4) = -1×1×-5 = 5

aha ! so, in order to get 10 instead of just 5 we must multiply the whole thing by 2.

as n×0 is always still 0, this does not change our 0 points (or roots).

so, our full function is :

f(x) = 2x(x + 2)(x - 4)

or, if you need the function as a polynomial, we need to do the multiplications :

f(x) = 2x(x² - 4x + 2x - 8) = 2x(x² - 2x - 8) = 2x³ - 4x² - 16x

3 0

2 years ago

What is the greatest common factors of 60w,34w^2,and 24w^4

andrew11 [14]

Answer: 2w

Step-by-step explanation:

The greatest common factor could also be referred to as the Highest common factor. Now

60w, 34w² and 24w⁴

Now let concert each to its factors

60 = 2 × 2 × 3 × 5 × w

34w² = 2 × 17 × w × w

24w⁴ = 2 × 2 × 2 × 3 × w × w × w × w

Therefore H.C.F or the greatest common factor

G.C.F = 2 × w

= 2w

4 0

3 years ago

A certain breed of mouse was introduced onto a small island with an initial population of 320 mice, and scientists estimate that

Viefleur [7K]

Y=2x+320
x being the number of years and 320 being the initial population of mice

7 0

3 years ago

CAN SOMEONE HELP ME WITH THESE QUESTIONS PLEASE!?

sukhopar [10]

Answer:

Step-by-step explanation:

1.

$(c+9)^2=64=8^2\\$

c+9=±8

either c=8-9=-1

c=-8-9=-17

so c=-1,-17

D

2.

8x^2-3=2

8x^2=5

$x^2=\frac{5}{8}=\frac{10}{16}$

$x=±\frac{\sqrt{10}}{4}$

so A

3.

$x^2+4x+4=18\\(x+2)^2=9*2\\x+2=3\sqrt{2} \\x=-2 ±3\sqrt{2}$

so D

or

8 0

3 years ago

Find the derivative.

Aleksandr [31]

Answer:

Using either method, we obtain: $t^\frac{3}{8}$

Step-by-step explanation:

a) By evaluating the integral:

$\frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du$

The integral itself can be evaluated by writing the root and exponent of the variable u as: $\sqrt[8]{u^3} =u^{\frac{3}{8}$

Then, an antiderivative of this is: $\frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}$

which evaluated between the limits of integration gives:

$\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}$

and now the derivative of this expression with respect to "t" is:

$\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}$

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

$g(x)=\int\limits^x_a {f(t)} \, dt$

is continuous on [a,b], differentiable on (a,b) and $g'(x)=f(x)$

Since this this function $u^{\frac{3}{8}$ is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

$\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}$

5 0

3 years ago

A x b = 400 a ÷ b = 4how much is b​

A x b = 400 a ÷ b = 4how much is b