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9966 [12]
3 years ago
6

Select the correct answer. What is the simplest form of this expression? (2x − 3)(3x2 + 2x − 1) A. 6x3 − 5x2 − 8x + 3 B. 6x3 − 5

x2 − 6x + 2 C. 6x3 − 9x2 − 4x + 3 D. 6x3 − 2x2 − 8x + 3
Mathematics
2 answers:
BabaBlast [244]3 years ago
7 0

Answer:

Step-by-step explanation:

So the 2 expressions are being multiplied:

(2x -3)((3x^2 +2x-1) =

(2x)3x2) = 6x^3

(2x)(2X) = 4X^2

(2X)(-1)=-2X

(-3)(3X^2) =-9X^2

(-3)(2X)=-6X

(-3)(-1)= 3

Now add all of the products together to get the final answer =

6x^3-5x^2-8x+3

noname [10]3 years ago
6 0

Answer: A. 6x3 − 5x2 − 8x + 3

Step-by-step explanation: this is a multiplication (2x − 3) = A (3x2 + 2x − 1) = B, so we are going to multiply each value from A with every value of B

for example you can start 2X from A

2X . 3X2 = 6X3

2X . 2X = 4X2

2X . -1 = -2X

now with -3

-3  . 3X2 = -9X2

-3 . 2X = -6X

-3  . 1 = -3

mow we can put every value in one equation

6X3 +  4X2 + 2X - 9X2 -6 X - 3

after that, you can simplify the common values for example

4X2 - 9X2 = -5x2

- 2X - 6 X  = -8x

this the last equation that we get after simplify

6x3 − 5x2 − 8x + 3

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<u>Answer-</u>

\boxed{\boxed{\frac{7}{3}}}

<u>Solution-</u>

Rational Root Theorem-

f(x)=a_nx^n+a_{n-1}x^{n-1}+a_{n-2}x^{n-2}+.......+a_1x+a_0\ \ \ and\ a_n\neq 0

All the potential rational roots are,

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a_n=9,\ a_0=7\\\\\text{factors of}\ 9=1,3,9\\\\\text{factors of}\ 7=1,7

The potential rational roots are,

=\pm \frac{1}{1},\pm \frac{1}{3}, \pm \frac{1}{9}, \pm \frac{7}{1}, \pm \frac{7}{3}, \pm \frac{7}{9}

=\pm 1,\pm \frac{1}{3}, \pm \frac{1}{9}, \pm 7, \pm \frac{7}{3}, \pm \frac{7}{9}

From, the given options only \frac{7}{3} satisfies.

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Answer:

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Step-by-step explanation:

<h3>Part A:</h3>

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