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Rainbow [258]
2 years ago
10

Find the value of x.

Mathematics
1 answer:
Tresset [83]2 years ago
8 0

Answer:

  x = 117

Step-by-step explanation:

The sum of the interior angles of a pentagon is 180°(5 -2) = 540°. This means ...

  x +59 +138 +140 +86 = 540

  x +423 = 540 . . . simplify

  x = 117 . . . . . . . . subtract 117

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Evaluate the function for the given values to determine if the value is a root. p(−2) = p(2) = The value is a root of p(x).
bija089 [108]

<em>Note: Since you missed to mention the the expression of the function </em>p(x)<em> . After a little research, I was able to find the complete question. So, I am assuming the expression as </em>p(x)=x^4-9x^2-4x+12<em> and will solve the question based on this assumption expression of  </em>p(x)<em>, which anyways would solve your query.</em>

Answer:

As

p\left(-2\right)=0

Therefore, x=-2 is a root of the polynomial <em> </em>p(x)=x^4-9x^2-4x+12

As

p\left(2\right)=-16

Therefore, x=2 is not a root of the polynomial <em> </em>p(x)=x^4-9x^2-4x+12

Step-by-step explanation:

As we know that for any polynomial let say<em> </em>p(x)<em>, </em>c is the root of the polynomial if p(c)=0.

In order to find which of the given values will be a root of the polynomial, p(x)=x^4-9x^2-4x+12<em>, </em>we must have to evaluate <em> </em>p(x)<em> </em>for each of these values to determine if the output of the function gets zero.

So,

Solving for p\left(-2\right)

<em> </em>p(x)=x^4-9x^2-4x+12

p\left(-2\right)=\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12

\mathrm{Simplify\:}\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12:\quad 0

\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12

\mathrm{Apply\:rule}\:-\left(-a\right)=a

=\left(-2\right)^4-9\left(-2\right)^2+4\cdot \:2+12

\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}

=2^4-2^2\cdot \:9+8+12

=2^4+20-2^2\cdot \:9

=16+20-36

=0

Thus,

p\left(-2\right)=0

Therefore, x=-2 is a root of the polynomial <em> </em>p(x)=x^4-9x^2-4x+12<em>.</em>

Now, solving for p\left(2\right)

<em> </em>p(x)=x^4-9x^2-4x+12

p\left(2\right)=\left(2\right)^4-9\left(2\right)^2-4\left(2\right)+12

\mathrm{Remove\:parentheses}:\quad \left(a\right)=a

p\left(2\right)=2^4-9\cdot \:2^2-4\cdot \:2+12

p\left(2\right)=2^4-2^2\cdot \:9-8+12

p\left(2\right)=2^4+4-2^2\cdot \:9

p\left(2\right)=16+4-36

p\left(2\right)=-16

Thus,

p\left(2\right)=-16

Therefore, x=2 is not a root of the polynomial <em> </em>p(x)=x^4-9x^2-4x+12<em>.</em>

Keywords: polynomial, root

Learn more about polynomial and root from brainly.com/question/8777476

#learnwithBrainly

7 0
3 years ago
Read 2 more answers
Expand 4x(7x-11)<br> For maths <br> Help please
harina [27]

Answer:

28x^2-44x

Step-by-step explanation:

Use the distributive property.

4x * 7x = 28x^2

4x * (-11) = -44x

We will get 28x^2-44x

Hope this helps!

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%20%7Bx%7D%5E%20%7B2%7D%20%20-%2029%20%3D%2052" id="TexFormula1" title=" {x}^ {2} - 29 =
AleksAgata [21]
X is equal to 9 and -9
4 0
3 years ago
I need help with this please
Kazeer [188]

Answer:

score = 63

Step-by-step explanation:

1.  To write the proportion take the score of the test over the number of points and set it equal to the percent over 100

score         90

----------- = -----------

70               100

Using cross products

100 * score = 90*70

100 score = 6300

Divide by 100

100/100 * score = 6300/100

score = 63

8 0
3 years ago
Help ASAP before 2:10
kirill115 [55]

Answer:3 choice

Step-by-step explanation:

When you have this || you put the opposite mark

5 0
3 years ago
Read 2 more answers
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