Ask question

Ask question

All categories

2 years ago

10

Find the value of x.

1 answer:

Tresset [83]2 years ago

8 0

Answer:

x = 117

Step-by-step explanation:

The sum of the interior angles of a pentagon is 180°(5 -2) = 540°. This means ...

x +59 +138 +140 +86 = 540

x +423 = 540 . . . simplify

x = 117 . . . . . . . . subtract 117

You might be interested in

Evaluate the function for the given values to determine if the value is a root. p(−2) = p(2) = The value is a root of p(x).

bija089 [108]

<em>Note: Since you missed to mention the the expression of the function </em> $p(x)$ <em> . After a little research, I was able to find the complete question. So, I am assuming the expression as </em> $p(x)=x^4-9x^2-4x+12$ <em> and will solve the question based on this assumption expression of </em> $p(x)$ <em>, which anyways would solve your query.</em>

Answer:

As

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$

As

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$

Step-by-step explanation:

As we know that for any polynomial let say<em> </em> $p(x)$ <em>, </em> $c$ is the root of the polynomial if $p(c)=0$ .

In order to find which of the given values will be a root of the polynomial, $p(x)=x^4-9x^2-4x+12$ <em>, </em>we must have to evaluate <em> </em> $p(x)$ <em> </em>for each of these values to determine if the output of the function gets zero.

So,

Solving for $p\left(-2\right)$

<em> </em> $p(x)=x^4-9x^2-4x+12$

$p\left(-2\right)=\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12$

$\mathrm{Simplify\:}\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12:\quad 0$

$\left(-2\right)^4-9\left(-2\right)^2-4\left(-2\right)+12$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$=\left(-2\right)^4-9\left(-2\right)^2+4\cdot \:2+12$

$\mathrm{Apply\:exponent\:rule}:\quad \left(-a\right)^n=a^n,\:\mathrm{if\:}n\mathrm{\:is\:even}$

$=2^4-2^2\cdot \:9+8+12$

$=2^4+20-2^2\cdot \:9$

$=16+20-36$

$=0$

Thus,

$p\left(-2\right)=0$

Therefore, $x=-2$ is a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$ <em>.</em>

Now, solving for $p\left(2\right)$

<em> </em> $p(x)=x^4-9x^2-4x+12$

$p\left(2\right)=\left(2\right)^4-9\left(2\right)^2-4\left(2\right)+12$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$p\left(2\right)=2^4-9\cdot \:2^2-4\cdot \:2+12$

$p\left(2\right)=2^4-2^2\cdot \:9-8+12$

$p\left(2\right)=2^4+4-2^2\cdot \:9$

$p\left(2\right)=16+4-36$

$p\left(2\right)=-16$

Thus,

$p\left(2\right)=-16$

Therefore, $x=2$ is not a root of the polynomial <em> </em> $p(x)=x^4-9x^2-4x+12$ <em>.</em>

Keywords: polynomial, root

Learn more about polynomial and root from brainly.com/question/8777476

#learnwithBrainly

7 0

3 years ago

Read 2 more answers

Expand 4x(7x-11)<br> For maths <br> Help please

harina [27]

Answer:

$28x^2-44x$

Step-by-step explanation:

Use the distributive property.

$4x * 7x = 28x^2$

$4x * (-11) = -44x$

We will get $28x^2-44x$

Hope this helps!

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%20%7Bx%7D%5E%20%7B2%7D%20%20-%2029%20%3D%2052" id="TexFormula1" title=" {x}^ {2} - 29 =

AleksAgata [21]

X is equal to 9 and -9

4 0

3 years ago

I need help with this please

Kazeer [188]

Answer:

score = 63

Step-by-step explanation:

1. To write the proportion take the score of the test over the number of points and set it equal to the percent over 100

score 90

----------- = -----------

70 100

Using cross products

100 * score = 90*70

100 score = 6300

Divide by 100

100/100 * score = 6300/100

score = 63

8 0

3 years ago

Help ASAP before 2:10

kirill115 [55]

Answer:3 choice

Step-by-step explanation:

When you have this || you put the opposite mark

5 0

3 years ago

Read 2 more answers