Answer:
Ok so the power of sussy is hard to find because you have to be sus which the impostor sus sussy then you sus more of the sus then you get the sus sus sus sus sus sus sus sus sus sus sus amogus.
Explanation:
Answer:
Check Explanation
Explanation:
A) the string (abbba) is not a word in this language because in this language, each b must preceded or followed by an a. Three consecutive b's are just not possible.
B) All the words with 3 letters in this language
aaa
aab
aba
baa
C) 5 words with four letters from this language. I'll write as many as possible to make things as easy as possible.
aaaa
aaab
aaba
baab
baba
baaa
abaa
abab
abba
D) This is the language of words without bbb, with every bb preceded and followed by an a (that is, no word can start or end wilth bb). All non-empty strings contain at least one a (so b and bb together are not allowed!).
Hope this Helps!!!
Answer:#include <stdio.h>
int main() {
int num;
printf("Enter an integer: ");
scanf("%d", &num);
// true if num is perfectly divisible by 2
if(num % 2 == 0)
printf("%d is even.", num);
else
printf("%d is odd.", num);
return 0;
}
1. Go to insert tab
2. Click the chart tab
3. Choose the type of chart
4. Click OK
List the poem please. I won’t be able to answer without it.
