Answer: 3.2x = 12.8
Step-by-step explanation: Lets have x equal each box that weighs 3.2 pounds.
The expression: 3.2x = 12.8 represents that each box, x of candies will weigh 3.2 pounds and the total weight of the candies will equal 12.8 pounds of candy.
Additional: There are 4 boxes of candy, 12.8 divided by 3.2 = 4
Answer:
<h2><em><u>Option</u></em><em><u> </u></em><em><u>B</u></em></h2><h2><em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>50</u></em><em><u>°</u></em><em><u> </u></em></h2>
Step-by-step explanation:
<em><u>By</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>condition</u></em><em><u>, </u></em>
25° + 105° + x = 180° <em>[</em><em>Angle</em><em> </em><em>sum</em><em> </em><em>property</em><em> </em><em>of</em><em> </em><em>triangle</em><em>]</em>
=> 130 + x = 180
=> x = 180 - 130
=> <em><u>x</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>50</u></em><em><u>°</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>
<h3>
Answer:</h3>
- <u>20</u> kg of 20%
- <u>80</u> kg of 60%
<h3>
Step-by-step explanation:</h3>
I like to use a little X diagram to work mixture problems like this. The constituent concentrations are on the left; the desired mix is in the middle, and the right legs of the X show the differences along the diagonal. These are the ratio numbers for the constituents. Reducing the ratio 32:8 gives 4:1, which totals 5 "ratio units". We need a total of 100 kg of alloy, so each "ratio unit" stands for 100 kg/5 = 20 kg of constituent.
That is, we need 80 kg of 60% alloy and 20 kg of 20% alloy for the product.
_____
<em>Using an equation</em>
If you want to write an equation for the amount of contributing alloy, it works best to let a variable represent the quantity of the highest-concentration contributor, the 60% alloy. Using x for the quantity of that (in kg), the amount of copper in the final alloy is ...
... 0.60x + 0.20(100 -x) = 0.52·100
... 0.40x = 32 . . . . . . . . . . .collect terms, subtract 20
... x = 32/0.40 = 80 . . . . . kg of 60% alloy
... (100 -80) = 20 . . . . . . . .kg of 20% alloy
Area: 3.14*10*10
=314
Perimeter: 3.14*20
=62.8