Answer:
0.0098
Step-by-step explanation:
Given,
- Probability of test is positive if the person has disease, P(T/D)=0.99
Probability of test is negative if the person has disease,
P(T'/D) = 1-0.99 = 0.01
- Probability of test is negative if the person hasn't disease, P(T'/D')= 0.99
Probability of test is positive if the person hasn't disease,
P(T/D') = 1 - 0.99 = 0.01
- Probability of occurrence of disease, P(D) = 0.0001
Probability of not occurrence of disease,
P(D) = 1 - 0.0001 = 0.9999
Probability that test will be positive either disease is present or not,
P(T) = P(T/D).P(D)+P(T/D').P(D')
=0.99 x 0.0001 + 0.01 x 0.9999
= 0.000099 + 0.009999
= 0.010098
So, the probability that the person will have disease if the test is positive,


= 0.0098
So, the required probability will be 0.0098.
Answer:
If P is a subset of Q, then by definition, every element of P is an element of Q. So, as Q contains P, every element in either P or Q is in Q, so the union is Q. For the second, every element of P and Q is in P, so the intersection is P.
Step-by-step explanation:
Answer:
1 one answer, 2 lot of answers, 3 no answer
Step-by-step explanation:
I have to go to bed sorry