Yea it is.4\5 is greater than 2
Answer:
The answer is "Options A, B, and E represent mutually exclusive events".
Step-by-step explanation:
Two occurrences that can happen immediately called mutually incompatible. Let's now glance at our options and figure out where the statements are mutually incompatible events.
In Option A: You could see that landing on an unwanted portion and arriving on 2 are events that are locally incompatible, even as undesirable portion contains 3 and 4, and 2 were shaded.
In Option B: Arriving on a shaded part and falling on 3 are also mutually incompatible because there are 3 on a windows azure.
In Option C: A darkened portion and an increasing amount can land while 2 would be an even number as well as on the shaded portion. That number is very much the same.
In Option D: At the same time as 4 is greater than 3 and it is situated upon an undistressed section, landing and attracting a number larger than 3 can happen.
In Option E: Landing on a shaded part and landing on even a shaded part is an excluding event, since shaders may either be shaded or unlit.
Answer:
y = |x| – 4
Step-by-step explanation:
If we substitute x as 0, we get -4 therefore this is the answer.
Answer:
a=216.
Step-by-step explanation:
What you do is you need to get a by itself.
a/6-11=25. You first add 11 to both sides.
a/6=36. Next you will times 6 on both sides to get
a=216 as your answer.
Domain is x # 0
A case of a polynomial