All categories

2 years ago

What is the most precise name for quadrilateral ABCD with vertices AC-

Mathematics

1 answer:

matrenka [14]2 years ago

3 0

Answer:

D I may not be correct-

Step-by-step explanation:

SORREYYYY if im not tell me

You might be interested in

Si al numerador de una fraccion se añade 5, el valor de la fraccion es 2, y si al numerador se resta 2, al valor de la fraccion

konstantin123 [22]

Answer:

Respuesta.- La fracción es 9/7

Step-by-step explanation:

1) Llamando X e Y a la fracción, tenemos: X/Y

Si al numerador se le añade 5, es decir X+5, el valor de la fracción es 2, luego:

(X+5)/Y = 2

Y si al numerador se le resta 2, es decir X-2, el valor de la fracción es 1, luego:

(X-2)/Y = 1

Juntando amabas ecuaciones:

(X+5)/Y= 2

(X-2)/Y = 1

Despejando Y en ambas:

Y = (X+5)/2

Y = (X-2)..........(1)

Igualandolas:

(X+5)/2= (X-2)

De donde:

X+5 = 2X-4

X = 9

Y finalmente, sustituyendo el valor de X = 9 en la ecuaión (1), tendremos:

Y = (X-2)

Y = (9-2)

Y = 7

Respuesta.- La fracción es 9/7

6 0

4 years ago

The function q = 230,000 -28p is a demand function which expresses the quantity demanded of a product q as a function of the pri

avanturin [10]

Answer:

D=[0, 8 214.29]

R=[0, 230 000]

Step-by-step explanation:

In order to find the domain, we must think of the least price you can give to the product you are selling. The price cannot be less than zero, since that would mean that you are giving money to the consumer for taking the product away, so zero is the smallest value p can get.

The greatest value the price can get is the one such that the quantity demanded is zero. So we need to determine that price by setting the equation equal to zero and solving for p.

230,000-28p=0

so we get

-28p=-230,000

$p=\frac{-230,000}{-28}$

p=$8,214.29

so the restricted domain for this function would be:

$0\leq p \leq 8,214.29$

or in interval notation:

D=[0, 8 214.29]

In order to find the range, we just need to determine what's the least and greatest value the function can get. Since this is a linear function, we can find them by just substituting each of the extreme values of the domain in the function, so we get:

q=230,000-28(0)=230,000

q=230,000-28(8214.29)=0

so the range would be:

$0\leq q \leq 230,000$