Is each a circle or are they going to be triangles because if so you would divide 5 by 2 and get your answer of 2.5 as the diameter for each slice but if it is circles you would divide 5/7 and get .71428......
Hello here is a solution :
<span>The polynomial is : (x+5)(x-2)(x-6)</span>
Answer:
1. Every zero is basically
![{10}^{1}](https://tex.z-dn.net/?f=%20%7B10%7D%5E%7B1%7D%20)
For example
![{10}^{1} = 10 \\ {10}^{2} = 100 \\ {10}^{3} = 100 \: \\ etc](https://tex.z-dn.net/?f=%20%7B10%7D%5E%7B1%7D%20%20%3D%2010%20%20%5C%5C%20%20%20%7B10%7D%5E%7B2%7D%20%20%3D%20100%20%5C%5C%20%20%7B10%7D%5E%7B3%7D%20%20%3D%20100%20%5C%3A%20%20%5C%5C%20etc)
2.
![when \: using \: 138 \: the \: scientific \: \\ is \: 1.38 \times {10}^{2} \: because \: ... \: see \: previous \\ \: example \: . \: the \: 1.38 \: is \: created \: due \: to \\ \: 138 \: being \: divided \: by \: 100 \: resulting \\ in \: 1.38](https://tex.z-dn.net/?f=when%20%5C%3A%20using%20%5C%3A%20138%20%5C%3A%20the%20%5C%3A%20scientific%20%5C%3A%20%20%5C%5C%20is%20%5C%3A%201.38%20%5Ctimes%20%20%7B10%7D%5E%7B2%7D%20%20%5C%3A%20because%20%5C%3A%20...%20%5C%3A%20see%20%5C%3A%20previous%20%5C%5C%20%20%5C%3A%20example%20%5C%3A%20%20.%20%5C%3A%20the%20%5C%3A%201.38%20%5C%3A%20is%20%5C%3A%20created%20%5C%3A%20due%20%5C%3A%20to%20%5C%5C%20%20%5C%3A%20138%20%5C%3A%20being%20%5C%3A%20divided%20%5C%3A%20by%20%5C%3A%20100%20%5C%3A%20resulting%20%5C%5C%20in%20%5C%3A%201.38)
3.
![the \: x \: in \: {10}^{x} \: is \: always \: equivalent \\ to \: the \: amount \: of \: zeros \: in \: the \: number \\ for \: example \: 100 = {10}^{2 } \\ 0.01 = {10}^{ - 2}](https://tex.z-dn.net/?f=the%20%5C%3A%20x%20%5C%3A%20in%20%5C%3A%20%20%7B10%7D%5E%7Bx%7D%20%20%5C%3A%20is%20%5C%3A%20always%20%5C%3A%20equivalent%20%5C%5C%20to%20%5C%3A%20the%20%5C%3A%20amount%20%5C%3A%20of%20%5C%3A%20zeros%20%5C%3A%20in%20%5C%3A%20the%20%5C%3A%20number%20%5C%5C%20for%20%5C%3A%20example%20%5C%3A%20100%20%3D%20%20%7B10%7D%5E%7B2%20%7D%20%20%5C%5C%200.01%20%3D%20%20%7B10%7D%5E%7B%20-%202%7D%20)
B.16 is the answer to your question