Answer:
Provided that the sample size, n, is sufficiently large (greater than 30), the distribution of sample means selected from a population will have a normal distribution, according to the Central Limit Theorem.
Explanation:
1. As n increases, the sample mean approaches the population mean
(The Law of Large numbers)
2. The standard error of the sample is
σ/√n
where σ = population standard deviation.
As n increases, the standard error decreases, which means that the error
between the sample and population means decreases.
Answer:1/2b^2
Step-by-step explanation: The square is b^2?
Answer:
The answer is "Option A and Option B".
Step-by-step explanation:
In question 1:
In all cases, the entire population is measured so that the actual medium discrepancy could be measured as well as an interval of trust cannot be used.
This issue would be that she calculated the ages with all representatives of both classes, such that she measured a whole population. It's not necessary.
In question 2:
When the p-value is 0.042. At 90% trust and 92% trust level 11 (p-value below 0.10 and 0.08) are not included. however the biggest confidence level of 92%. Consequently, the largest trust level where the 11 is Not included in the trust interval is 92% trust.
Answer:
Step-by-step explanation:
as said in my comment
A: (3x-2)X(x+1)
B: substitute 3 in(if m=meters),
(3x3-2)
9-2
7X(x+1)
3+1
4
7X4
28
X=2→F(2)=[(2)^3+3]/[(2)^2-5]
F(2)=(8+3)/(4-5)
F(2)=11/(-1)
F(2)=-11
-2/F(2)=-2/(-11)
-2/F(2)=2/11
Answer: 2/11