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skad [1K]
2 years ago
5

I need help with this please!!

Mathematics
1 answer:
astraxan [27]2 years ago
3 0

Answer:

-4

It would be -4 because the midpoint of a line is the point thats right in the middle.

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LAU
luda_lava [24]

Answer:

A.The marginal frequency for the survey is 160

Step-by-step explanation:

3 0
3 years ago
M=3 (1,5) in slope intercept form
ra1l [238]

Answer:

y=3x+5

Step-by-step explanation:

6 0
3 years ago
Can someone help me solve this differentiation/tangent problem?
nirvana33 [79]
A)

\bf g'(x)=\stackrel{product~rule}{2x\cdot f(x)+x^2\cdot  f'(x)}\quad 
\begin{cases}
x=5\\
f(5)=5\\
f'(5)=5
\end{cases}
\\\\\\
g'(5)=2(5)\cdot f(5)+(5)^2\cdot f'(5)\implies g'(5)=50+500\\\\\\ g'(5)=550\\\\
-------------------------------\\\\
g(5)=(5)^2f(5)\implies g(5)=125
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}
\begin{cases}
x=5\\
y=125\\
\stackrel{m}{g'(5)}=550
\end{cases}\implies y-125=550(x-5)
\\\\\\
y-125=550x-2750\implies y=550x+400



b)

\bf h'(x)=\stackrel{quotient~rule}{\cfrac{f'(x)(x-6)~~-~~f(x)\cdot 1}{(x-6)^2}}\quad 
\begin{cases}
x=5\\
f(5)=5\\
f'(5)=5
\end{cases}
\\\\\\
h'(5)=\cfrac{f'(5)(5-6)~~-~~f(5)\cdot 1}{(5-6)^2}
\\\\\\
h'(5)=\cfrac{5(-1)-5}{(-1)^2}\implies h'(5)=-10\\\\
-------------------------------\\\\

\bf h(5)=\cfrac{f(5)}{5-6}\implies h(5)=\cfrac{5}{-1}\implies h(5)=-5
\\\\\\
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\quad 
\begin{cases}
x=5\\
y=-5\\
\stackrel{m}{-10}
\end{cases}\implies y-(-5)=-10(x-5)
\\\\\\
y+5=-10x+50\implies y=-10x+45
3 0
4 years ago
Which expression is equivalent to 5(x + 2) - 7(x + 2)?
Harman [31]
The answer is
A: -2x - 4

I did the math and that’s what I got so I hope it helped!
6 0
3 years ago
What is <br><br><br> 647.15 as a decimal
Katena32 [7]

Answer:

Its already a decimal bud - Lily ^_^

Step-by-step explanation:

8 0
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