Cubes have 6 numbers
3 odd, 3 even
probablity=desiredoutcome/totalpossibleoutcomes
there are 6 total desired outcomes (3 on each cube)
total possible, there are 6*6 or 36 total possible outcomes
so 6/36 or 1/6 chance
Check the picture below.
so the area of the hexagon is really just the area of two isosceles trapezoids.
![\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ a=2\\ b=4\\ h=2 \end{cases}\implies \begin{array}{llll} A=\cfrac{2(2+4)}{2}\implies A=6 \\\\\\ \stackrel{\textit{twice that much}}{2A = 12} \end{array}](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%20%5Cbegin%7Bcases%7D%20h%3Dheight%5C%5C%20a%2Cb%3D%5Cstackrel%7Bparallel~sides%7D%7Bbases%7D%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3D2%5C%5C%20b%3D4%5C%5C%20h%3D2%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20A%3D%5Ccfrac%7B2%282%2B4%29%7D%7B2%7D%5Cimplies%20A%3D6%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Btwice%20that%20much%7D%7D%7B2A%20%3D%2012%7D%20%5Cend%7Barray%7D)
Answer:
1/4
Step-by-step explanation:
3/12 = 1/4
(We got 12 by adding all the numbers together.)
Find the total number of dogs by adding each day:
Total dogs = 23
Percent of dogs: Divide the number of dogs by the total number of patients:
= 23 / 50 = 0.46 x 100 = 46%
Use the given formula to find the standard error:
Standard error = √(0.46*(1-0.46)/50) = 0.07
90%: Find Z value for 90% ( 1.645) multiply by SE:
1.645 x 0.07 = 0.115 = 0.12
Now add and subtract that value from the Percent from above:
46 + 12 = 58%
46-12 = 34%
Answer (34%, 58%)
95%: Find Z value for 95% ( 1.96) multiply by SE:
1.96 x 0.07 = 0.137 = 0.14
Now add and subtract that value from the Percent from above:
46 + 14 = 60%
46-14 = 32%
Answer (32%, 60%)
Answer:
thx i ned the points lol
Step-by-step explanation:
bErS
