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2 years ago

How are lines of longitude measure to the east of the prime meridian

1 answer:

6 0

Longitude is the measurement east or west of the prime meridian. Longitude is measured by imaginary lines that run around the Earth vertically (up and down) and meet at the North and South Poles. ... Each meridian measures one arcdegree of longitude. The distance around the Earth measures 360 degrees.

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Imagine that you have obtained spectra for several galaxies and have measured the observed wavelength of a hydrogen emission lin

Lerok [7]

Answer:

A. z (galaxy 1) = -0.00515, z (galaxy 2) = -0.01707, z (galaxy 3) = -0.04008

B. v (galaxy 1) = -0.00517c, v (galaxy 2) = -0.01707c, v (galaxy 3) = -0.0401c

C. d (galaxy 1) = -21 Mpc,d (galaxy 2) = -69.4 Mpc, d (galaxy 3) = -163 Mpc

Explanation:

We begin by listing out the parameters we were given:

λ (obsv) = 656.3 nm, λ (emit 1) = 659.7 nm, λ (emit 2) = 667.7 nm,

λ (emit 3) = 683.7 nm

A) Using the Redshift formula, we have:

z = [λ (obsv) - λ (emit)] ÷ λ (emit)

For galaxy 1:

z = [λ (obsv) - λ (emit 1)] ÷ λ (emit 1)

z = (656.3 - 659.7) ÷ 659.7 = -0.00515

z = -0.00515

For galaxy 2:

z = [λ (obsv) - λ (emit 2)] ÷ λ (emit 2)

z = (656.3 - 667.7) ÷ 667.7 = -0.01707

z = -0.01707

For galaxy 3:

z = [λ (obsv) - λ (emit 3)] ÷ λ (emit 3)

z = (656.3 - 683.7) ÷ 683.7 = -0.04008

z = -0.04008

B) Using the Doppler formula, we have:

(Δλ ÷ λ) = v ÷ c

v = c * (Δλ ÷ λ)

but, z = (Δλ ÷ λ)

⇒ v = c * z

speed of light (c) = 3 x $10^{8}$ m/s

For galaxy 1:

v = c * z

Substitute z into the equation calculated from A) above

v = 3 x $10^{8}$ * (-0.00515)

v = -1.55 x $10^{6}$ m/s

v = -0.00517c

For galaxy 2:

v = c * z

Substitute z into the equation calculated from A) above

v = 3 x $10^{8}$ * (-0.01707)

v = -5.12 x $10^{6}$ m/s

v = -0.01707c

For galaxy 3:

v = c * z

Substitute z into the equation calculated from A) above

v = 3 x $10^{8}$ * (-0.04008)

v = -12.03 x $10^{6}$ m/s

v = -0.0401c

N.B: the negative value of velocity connotes that the galaxies are moving away from us (not towards us)

C) Using Hubbleʹs law, we have:

v = H · d

where:

v = velocity of a galaxy (km/s), d = distance (Mpc),

H = Hubble's constant (km/s/Mpc) = 73.8 km/sec

d = v ÷ H

We use the velocities calculated in B) above

For galaxy 1:

v = -1.55 x $10^{3}$ km/s

d = -1.55 x $10^{3}$ ÷ 73.8

d = -21 Mpc

For galaxy 2:

v = -5.12 x $10^{3}$ km/s

d = -5.12 x $10^{3}$ ÷ 73.8

d = -69.4 Mpc

For galaxy 3:

v = -12.03 x $10^{3}$ km/s

d = -12.03 x $10^{3}$ ÷ 73.8

d = -163 Mpc

N.B: distance cannot be a negative value

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3 years ago

The sparkling boom was both _____ and _____ when the fireworks exploded last night.

Zielflug [23.3K]

Dazzling and bright
Hope it helps!
#MissionExam001

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3 years ago

I want to study marine life, like dolphins and sharks. I should learn about _____.

ANEK [815]

You should learn oceanology and also geography,biology.

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3 years ago

Read 2 more answers

The United States buys much of its oil from OPEC countries. How would an increase in prices affect the daily lives of people in

djyliett [7]

Answer:

Brainliest pls

Explanation:

The OPEC oil embargo was an event where the 12 countries that made up OPEC stopped selling oil to the United States. The embargo sent gas prices through the roof. Between 1973-1974, prices more than quadrupled. The embargo contributed to stagflation.

The Organization of the Petroleum Exporting Countries (OPEC) then took over, ruling the oil markets and oil prices in the years that followed. However, with the discovery of shale oil in the U.S. and advances in drilling techniques, the U.S. has since re-emerged as a top energy producer.

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3 years ago

Explain why it is necessary to protect the sand spit from coastal erosion.

vovikov84 [41]

Answer: Because sand dunes protect inland areas from swells, tides, and winds, they must be protected and defended like national treasures. A strong and healthy beach dune is a powerful antidote against coastal erosion. The ocean and the wind can have an unpredictable, destructive force on coastal regions.

7 0

3 years ago