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2 years ago

A system of equations is shown below.

Mathematics

2 answers:

LenKa [72]2 years ago

6 0

3x-2y=7 9x-6y=k
No solution

GarryVolchara [31]2 years ago

4 0

<h3>Answer: Choice C</h3>

No solutions if k is anything but 21

=======================================================

Explanation:

Let's multiply everything in the first equation by 3

3x-2y = 7

3*(3x-2y) = 3*7

9x - 6y = 21

We have the 9x-6y match perfectly with the left hand side of the second original equation.

If k = 21, then we have two identical equations that produce infinitely many solutions.

If $k \ne 21$ , then this system is inconsistent and has no solutions.

You might be interested in

A player of the National Basketball Association’s Portland Trail Blazers is the best free-throw shooter on the team, making 94%

g100num [7]

Answer:

The data for the probabilities are shown in the table below.

- A represents the probability of making the two shots for each of the best and worst shooter on the Portland Trail Blazers' team

- B represents the probability of making at least one shot for each of the best and worst shooter on the Portland Trail Blazers' team.

- C represents the probability of not making any of the two shots for each of the best and worst shooter on the Portland Trail Blazers' team.

N | Best ||| Worst

A | 0.8836 | 0.3136

B | 0.9964 | 0.8064

C | 0.0036 | 0.1936

It becomes evident why fouling the worst shooter on the team is a better tactic. The probabilities of the best shooter making the basket over the range of those two free shots are way better than the chances for the worst shooter.

Step-by-step explanation:

Part 1

Probability of the best shooter of the National Basketball Association’s Portland Trail Blazers making a shot = P(B) = 94% = 0.94

Probability that he doesn't make a shot = P(B') = 1 - 0.94 = 0.06

a) Probability that the best shooter on the team makes the two shots awarded = P(B) × P(B) = 0.94 × 0.94 = 0.8836

b) Probability that the best shooter on the team makes at least one shot.

This is a sum of probabilities that he makes only one shot and that he makes two shots.

Probability that he makes only one shot

= P(B) × P(B') + P(B') + P(B)

= (0.94 × 0.06) + (0.06 × 0.94) = 0.1128

Probability that he makes two shots = 0.8836 (already calculated in part a)

Probability that he makes at least one shot = 0.1128 + 0.8836 = 0.9964

c) Probability that the best shooter on the team makes none of the two shots = P(B') × P(B') = 0.06 × 0.06 = 0.0036

d) If the worst shooter on the team, whose success rate is 56% is now fouled to take the two shots.

Probability of the worst shooter on the team making a shot = P(W) = 56% = 0.56

Probability that the worst shooter on the team misses a shot = P(W') = 1 - 0.56 = 0.44

Part 2

a) Probability that the worst shooter on the team makes the two shots = P(W) × P(W)

= 0.56 × 0.56 = 0.3136

b) Probability that the worst shooter on the team makes at least one shot.

This is a sum of probabilities that he makes only one shot and that he makes two shots.

Probability that he makes only one shot

= P(W) × P(W') + P(W') + P(W)

= (0.56 × 0.44) + (0.44 × 0.56) = 0.4928

Probability that he makes two shots = 0.3136 (already calculated in part a)

Probability that he makes at least one shot = 0.4928 + 0.3136 = 0.8064

c) Probability that the worst shooter makes none of the two shots = P(W') × P(W') = 0.06 × 0.06 = 0.1936

From the probabilities obtained

N | Best ||| Worst

A | 0.8836 | 0.3136

B | 0.9964 | 0.8064

C | 0.0036 | 0.1936

Hope this Helps!!!

8 0

3 years ago

Read 2 more answers

If each value of the data of the poplation function is doubled which of the following is not correct?

Anna35 [415]

Answer:

The variance is doubled; C

Step-by-step explanation:

Here, we want to select what will be wrong if every number in the dataset is doubled

A. This is correct

The mean is the average of the numbers which is calculated by dividing the sum of the numbers by the count of the numbers

By doubling the numbers, we have simply doubled the sum while the count is same

So what we have as the result of the division will be 2 times what we had initially making the mean doubled

B. The mode is doubled

Yes, this is correct

The mode is the highest in frequency

Doubling all numbers will not double their frequencies but their values. So the number that was the mode in the previous case will be the same but now doubled

D. The median is doubled

This is correct

The median deals with the middle number.

Since all numbers are doubled in the present case, the median to is also doubled along side as the numbers are now twice what they were evenly

C. This is wrong

The variance has to do with the spread of data

We are actually subtracting values

Since we are doubling across board, the difference between the numbers is the same as this, the variance cannot change

We can look at this from the angle that all others are measures of central tendency looking at having a central figure while the variance is a measure of spread.

3 0

3 years ago

Can someone help please and thank you

denis-greek [22]

Try making a grid like this. Apologies for the terrible drawing and handwriting. It represents all possible results of rolling two dice and summing their values. The blue column and yellow row represent the values of each die, and the green numbers reptesent their sums.
First, you can see that there are 36 possible values. Second, it's easy to see how many results are greater than 9, since they're all in one corner. And last, you can see just how many are even and how many are odd. Remember to reduce your fractions in the end.