<span>For a parallelogram to be proven to be a rectange, the opposide sides must be parallel and the two adjacent sides must be perpendicular.
For two parallel sides, the slope of the two sides is equal.
Thus, for the parallelogram to be a rectangle, AB is parallel to CD.
The slope of AB = (y2 - y1)/(x2 - x1) while the slope of CD = (y4 - y3)/(x4 - x3)
Also, BC is perpedicular to CD.
For two perpendicular sides, the product of the slopes is -1.
The slope of BC is given by (y3 - y2)/(x3 - x2).
Therefore, for the parallelogram to be a rectangle.
(y2 - y1)/(x2 - x1) = (y4 - y3)/(x4 - x3) and (y4 - y3)/(x4 - x3) x (y3 - y2)/(x3 - x2) = -1.
The third option is the correct answer.</span>
Answer:
6 zeros
Step-by-step explanation:
5000000
U 2 can help me by marking as brainliest.....
Answer: I know that the answer is 47.
Step-by-step explanation: add up all the angles to get 180 degrees.
Answer:
![-\frac{3\sqrt[3]{t} }{2}](https://tex.z-dn.net/?f=-%5Cfrac%7B3%5Csqrt%5B3%5D%7Bt%7D%20%7D%7B2%7D)
Step-by-step explanation:
1: Write g(t) as y, resulting in 
2: Interchange the variables y and t, resulting in 
3: Multiply both sides by 27, resulting in 
4: Divide both sides by -8, resulting in 
5: Find the cube root of both sides, resulting in ![\sqrt[3]{-\frac{27t}{8} }=y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-%5Cfrac%7B27t%7D%7B8%7D%20%7D%3Dy)
6: Apply a radical rule, resulting in ![-\sqrt[3]{\frac{27t}{8} } =y](https://tex.z-dn.net/?f=-%5Csqrt%5B3%5D%7B%5Cfrac%7B27t%7D%7B8%7D%20%7D%20%3Dy)
7: Apply another radical rule, resulting in ![-\frac{\sqrt[3]{27t} }{\sqrt[3]{8} } =y](https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%5B3%5D%7B27t%7D%20%7D%7B%5Csqrt%5B3%5D%7B8%7D%20%7D%20%3Dy)
8: Simplify the denominator, resulting in ![-\frac{\sqrt[3]{27t} }{2} =y](https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%5B3%5D%7B27t%7D%20%7D%7B2%7D%20%3Dy)
9: Apply yet another radical rule, resulting in ![-\frac{\sqrt[3]{27}\sqrt[3]{t} }{2} =y](https://tex.z-dn.net/?f=-%5Cfrac%7B%5Csqrt%5B3%5D%7B27%7D%5Csqrt%5B3%5D%7Bt%7D%20%20%20%7D%7B2%7D%20%3Dy)
10: Simplify
, resulting in ![-\frac{3\sqrt[3]{t} }{2} =y](https://tex.z-dn.net/?f=-%5Cfrac%7B3%5Csqrt%5B3%5D%7Bt%7D%20%20%20%7D%7B2%7D%20%3Dy)
Answer:
<u> BC = 10 and AD = 30</u>
Step-by-step explanation:
In figure-1 , AB = CD ,BK ⊥ AD, AK = 10, KD = 20.
Since, line AD is sum of AK and KD, then
AD = AK + KD
AD = 10 + 20
AD = 30
Since, BC ║AD and BK ⊥ AD then similarly we construct CL ⊥ AD
so, BC = KL and AK = LD
KL = AD - LD
KL = 20 - 10
KL = 10
Since, BC = KL then BC = 10
Hence, <u> BC = 10 and AD = 30</u>