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DENIUS [597]
3 years ago
14

AJJ -15 1. Which of the following shows the relationship between ? 7 21 = 1 and 2 c= -15 -15 - 15 A. => 3 B B.=< 21 21 21​

Mathematics
1 answer:
Fiesta28 [93]3 years ago
4 0

Answer:

CV for your email is not available on the answer to write

Step-by-step explanation:

DF Mexico city Mexico city Mexico

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The vertices of a parallelogram are A(x1,y1), B(x2,y2), C(x3,y3), D(x4,y4)
Tju [1.3M]
<span>For a parallelogram to be proven to be a rectange, the opposide sides must be parallel and the two adjacent sides must be perpendicular. For two parallel sides, the slope of the two sides is equal. Thus, for the parallelogram to be a rectangle, AB is parallel to CD. The slope of AB = (y2 - y1)/(x2 - x1) while the slope of CD = (y4 - y3)/(x4 - x3) Also, BC is perpedicular to CD. For two perpendicular sides, the product of the slopes is -1. The slope of BC is given by (y3 - y2)/(x3 - x2). Therefore, for the parallelogram to be a rectangle. (y2 - y1)/(x2 - x1) = (y4 - y3)/(x4 - x3) and (y4 - y3)/(x4 - x3) x (y3 - y2)/(x3 - x2) = -1. The third option is the correct answer.</span>
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3 years ago
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How much ceros have 5 million?
Mandarinka [93]

Answer:

6 zeros

Step-by-step explanation:

5000000

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3 0
2 years ago
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Help I need to pass test
rewona [7]

Answer: I know that the answer is 47.

Step-by-step explanation: add up all the angles to get 180 degrees.

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3 years ago
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Help me please by solving and showing the steps:)
Lorico [155]

Answer:

-\frac{3\sqrt[3]{t} }{2}

Step-by-step explanation:

1: Write g(t) as y, resulting in y=-\frac{8}{27}t^3

2: Interchange the variables y and t, resulting in t=-\frac{8}{27}y^3

3: Multiply both sides by 27, resulting in 27t=-8y^3

4: Divide both sides by -8, resulting in -\frac{27t}{8}=y^3

5: Find the cube root of both sides, resulting in \sqrt[3]{-\frac{27t}{8} }=y

6: Apply a radical rule, resulting in -\sqrt[3]{\frac{27t}{8} } =y

7: Apply another radical rule, resulting in -\frac{\sqrt[3]{27t} }{\sqrt[3]{8} } =y

8: Simplify the denominator, resulting in  -\frac{\sqrt[3]{27t} }{2} =y

9: Apply yet another radical rule, resulting in -\frac{\sqrt[3]{27}\sqrt[3]{t}   }{2} =y

10: Simplify \sqrt[3]{27}, resulting in -\frac{3\sqrt[3]{t}   }{2} =y

3 0
3 years ago
Given: ABCD is a trapezoid, AB = CD, BK ⊥ AD, AK = 10, KD = 20 Find: BC AD
alexdok [17]

Answer:

<u> BC = 10 and AD = 30</u>

Step-by-step explanation:

In figure-1 , AB = CD ,BK ⊥ AD,  AK = 10,  KD = 20.

Since, line AD is sum of AK and  KD, then

AD = AK + KD

AD = 10 + 20

AD = 30

Since, BC ║AD and BK ⊥ AD then similarly we construct CL ⊥ AD

so, BC = KL and AK = LD

KL = AD - LD

KL = 20 - 10

KL = 10

Since, BC = KL then BC = 10

Hence, <u> BC = 10 and AD = 30</u>

4 0
3 years ago
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