1. x=3.03
2.x=0.5
3.x=4/3
4.x=2
5.x=10
Step 1: Subtract 63 from both sides.<span><span><span><span><span>x2</span>−<span>14x</span></span>+31</span>−63</span>=<span>63−63</span></span><span><span><span><span>x2</span>−<span>14x</span></span>−32</span>=0</span>Step 2: Factor left side of equation.<span><span><span>(<span>x+2</span>)</span><span>(<span>x−16</span>)</span></span>=0</span>Step 3: Set factors equal to 0.<span><span><span>x+2</span>=<span><span><span>0<span> or </span></span>x</span>−16</span></span>=0</span><span><span>x=<span>−<span><span>2<span> or </span></span>x</span></span></span>=16</span>Answer:<span><span>x=<span>−<span><span>2<span> or </span></span>x</span></span></span>=<span>16</span></span>
Answer:
16 pounds.
Step-by-step explanation:
As you said, objects weigh 6 times more than what they weigh on the moon. Therefore, the robot originally weighing 96 pounds will be reduced to 16 pounds.
16*6=96. (Original Weight)
96/6=16. (Weight after being on the moon.)
Answer:
r = 3.2
Step-by-step explanation:
If A varies inversely with the square of r, then A = kr^2
75 = k*4^2 = 16k
k = 75/16
Now A = (75/16)*r^2
48 = (75/16)*r^2
r^2 = 48(16/75) = 256/25
r = 
= 16/5 = 3.2
