Answer:
They have to drive
miles more
Step-by-step explanation:
Given:
Total Distance of the road trip =
miles
Distance travelled already =
miles.
To Find:
How much farther do they have to drive = ?
Solution:
The distance they have to travel farther = Total distance - distance travelled
The distance they have to travel farther = ![32 \frac{3}{4} - 12 \frac{1}{2}](https://tex.z-dn.net/?f=32%20%5Cfrac%7B3%7D%7B4%7D%20%20-%20%2012%20%5Cfrac%7B1%7D%7B2%7D)
=>![\frac{128 + 3}{4} - \frac{24 +1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B128%20%2B%203%7D%7B4%7D%20%20-%20%20%5Cfrac%7B24%20%2B1%7D%7B2%7D)
=>![\frac{131}{4} - \frac{25}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B131%7D%7B4%7D%20%20-%20%20%5Cfrac%7B25%7D%7B2%7D)
=>![\frac{131- 50}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B131-%2050%7D%7B4%7D)
=>![\frac{81}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B81%7D%7B4%7D)
=>![20\frac{1}{4}](https://tex.z-dn.net/?f=20%5Cfrac%7B1%7D%7B4%7D)
The value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.
<h3>What is a linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have a system of the equation:
3y=x-2 ..(1)
y=-2x+4 ...(2)
From the equation (2) take the value of y and plug in the equation (1)
3(-2x+4) = x -2
-6x + 12 = x - 2
7x = 14
x = 14/7
x = 2
Plug this value in the equation (2)
y = -2(2) + 4
y = 0
Thus, the value of the x is 2 and the value of the y is 0 in the system of equation 3y=x-2, y=-2x+4.
Learn more about the linear equation here:
brainly.com/question/11897796
#SPJ1
F(X)=13 Just Plug 10 into the X in the equation
Step-by-step explanation:
First divide 1100 by 2
550
Now that would be the amount the both of them would have to pay if they were splitting it equally. Since there not add 250 to 550.
250+550=800
Finally subtract 250 from 550
550-250=300
Jake has to pay $550
Danny has to pay $300