Answer:
Step-by-step explanation:
A line passes through the point (–6, –2), and its y-intercept is (0, 1). What is the equation of the line that is perpendicular to this line and passes through the point (2, 3)?
Answer:
![15 \sqrt[3]{2}](https://tex.z-dn.net/?f=15%20%5Csqrt%5B3%5D%7B2%7D%20)
Step-by-step explanation:
![{(27 \times 250)}^{ \frac{1}{3} } = {(27 \times 125 \times 2)}^{ \frac{1}{3} } \\ = {27}^{ \frac{1}{3} } \times {125}^{ \frac{1}{3} } \times {2}^{ \frac{1}{3} } \\ = \sqrt[ 3]{27} \times \sqrt[3]{125} \times \sqrt[3]{2} \\ = \sqrt[3]{ {3}^{3} } \times \sqrt[3]{ {5}^{3} } \times \sqrt[3]{2} \\ = 3 \times 5 \times \sqrt[3]{2} \\ = 15 \sqrt[3]{2}](https://tex.z-dn.net/?f=%20%7B%2827%20%5Ctimes%20250%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%20%20%7B%2827%20%5Ctimes%20125%20%5Ctimes%202%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%7B27%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%5Ctimes%20%20%7B125%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%5Ctimes%20%20%7B2%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%5B%203%5D%7B27%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B125%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B2%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%5B3%5D%7B%20%7B3%7D%5E%7B3%7D%20%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B%20%7B5%7D%5E%7B3%7D%20%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B2%7D%20%20%5C%5C%20%20%3D%203%20%5Ctimes%205%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B2%7D%20%20%5C%5C%20%20%3D%2015%20%5Csqrt%5B3%5D%7B2%7D%20)
Answer:
It should take about 4.75 min.
Step-by-step explanation:
Hope this helps and could you mark me as the brainliest
Well, the chances are 3 to 1 in the first question, because there are three pencils and only one pen. In the second box it is a 50-50 chance that you will pick a crayon, because there are equal amounts of colored pencils and crayons in the second box. The numbers that I gave you aren't the fractions though. See if you can go from here.
Answer:
x - 2 ≥ 0
Step-by-step explanation:
The expression under the square root cannot be negative, thus
x - 2 ≥ 0 , that is
x ≥ 2
