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Oksana_A [137]
2 years ago
13

4x + 10y = 2 -4x + 8y = 16

Mathematics
2 answers:
LUCKY_DIMON [66]2 years ago
6 0

Answer:

  • One solution

Kind Note:

This question is incomplete. You need to provide the question in order to get the best answer on brainly. In this answer, I will tell you how many solutions are in this system of equations.

Step-by-step explanation:

This question involves the use of 'system of equations'.

  • => 4x + 10y = 2

            -4x + 8y = 16

  • => (4x - 4x) + (10y + 8y) = (2 + 16)
  • => 18y = 18
  • => y = 1 (No further check required)

Since the y-intercept is valid, the system of equations has one solution.

Hence, this system of equations has one solution.

Hoped this helped!

alexdok [17]2 years ago
5 0

32x + 80y = 8y - 4x

36x = -72y

x = -2y

2y = 2

y = 1

x = -2

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ELEN [110]

Answer:

The answer is C.  11/29

Step-by-step explanation:

Simplify the left side.

29a - 5 = 6

Move all terms not containing  a  to the right side of the equation.

29a = 11

Divide each term by  29  and simplify.

a =  11 /29

5 0
3 years ago
10+8=18 what number sentence should I write
dmitriy555 [2]

There are many different ways to write this sentence. Here are a couple of possible ways:

"The sum of 10 and 8 is 18"

"10 plus 8 equals 18"

3 0
3 years ago
A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6
galina1969 [7]
<h2>Hello!</h2>

The answers are:

a) The height of the ball after 3 seconds is 49 feet.

b) The maximum height of the ball is 66 feet.

c) That the ball hit the ground after 4 seconds.

d) The domain would be only the positive real numbers, from 0 to 4, since we found that the ball hit the ground at t equal to 4 seconds. However, if we were talking about a quadratic function with no time involved, the domain would be all the real numbers.

<h2>Why?</h2>

Since we are working with a quadratic function which describes the ball's motion in function of the time, we need to remember the following:

- The general equation of the parabola is:

y=ax^{2} +bx+c

- We can calculate the coordinates of the vertex of the parabola using the following formula:

x_{vertex}=\frac{-b}{2a}

- Evaluating a function means replacing the variable with the given value to evaluate.

The given function is:

h(t)=-16x^{2}+63t+4

Where,

a=-16\\b=63\\c=4

Now, calculating we have:

a) What is the height of the ball after 3 seconds?

We need to evaluate the time of 3 seconds into the function, so:

h(3)=-16(3)^{2} +63(3)+4=49feet

So, the height of the ball after 3 seconds is 49 feet.

b) What is the maximum height of the ball?

Since the function is describing the motion of a ball thrown into the air, we can find the maximum height by finding the y-coordinate of the vertex. If the parabola opens downward or upward, the vertex will be always the highest or the lowest point of the parabola.

So, calculating the vertex we have:

x_{vertex}=\frac{-b}{2a}=\frac{-63}{2*-16}\\\\x_{vertex}=\frac{-63}{2*-16}=\frac{-63}{-32}=1.97

Then, replacing "x" into the equation of the parabola, we find the y-coordinate of the vertex:

y=-16(1.97)^{2}+63(1.97)+4=-16*3.88+63*1.97+4\\y=-16*3.88+63*1.97+4=-62.08+124.11+4=66.03

So, if the y-coordinate is 66.03, the maximum height of the ball is 66.03 feet, or 66 feet (rounded to the nearest foot).

c) When will the ball hit the ground?

We can find the time when the ball hit the ground by making equal to 0 the function and finding the roots (zeroes)

Since it's a quadratic function, we can find the zeroes using the quadratic equation:

\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

Substituting a, b and c, we have:

\frac{-b+-\sqrt{b^{2}-4ac } }{2a}=\frac{-63+-\sqrt{63^{2}-4*(-16)*(4)} }{2*(-16)}\\\\\frac{-63+-\sqrt{63^{2}-4*(-16)*(4)} }{2*(-16)}=\frac{-63+-\sqrt{3969+256} }{-32}\\\\\frac{-63+-\sqrt{3969+256} }{-32}=\frac{-63+-\sqrt{4225} }{-32}=\frac{-63+-(65)}{-32}\\\\t1=\frac{-63-(65)}{-32}=4\\\\t1=\frac{-63+(65)}{-32}=-0.06

Now, since negative time does not exists, we can conclude that the ball hit the ground after 4 seconds.

d) what domain makes sense for the function?

Since the function represents the motion of the thrown ball at "t" time, the domain would be only the positive real numbers, from 0 to 4, since we found that the ball hit the ground at t equal to 4 seconds. However, if we were talking about a quadratic function with no time involved, the domain would be all the real numbers,

Note: I've attached the graph of the function.

Have a nice day!

5 0
3 years ago
Hi. I really need help with this question. I tried it myself but don't fully understand, so could someone please check it for me
Reil [10]

Answer:

C.

Step-by-step explanation:

that is the correct answer

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4 years ago
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jekas [21]
The second one is correct
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4 years ago
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