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2 years ago

Seven less than three times a number is 5. Find the number

Mathematics

2 answers:

Anit [1.1K]2 years ago

7 0

Step-by-step explanation:

it is 12 because 12 - 7 is 5 the number 4 is the number multiplied by 3

bagirrra123 [75]2 years ago

5 0

Answer:

the number is 4

Explanation:

let the number be b :)

3b - 7 = 5 { three times a number; seven less of that number; is 5 }

3b = 5 + 7 { changed sides }

3b = 12 { divide both sides by 3 }

b = 4 { final answer }

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last year price=$67

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2 years ago

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2 years ago

Use a reference angle to write sec255∘ in terms of the secant of a positive acute angle. Do not include the degree symbol in you

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Step-by-step explanation:

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3 years ago

Solve the following inequality. Then place the correct answer in the box provided. Answer in terms of a mixed number. 2(P +1) +

Darina [25.2K]

Answer:

$P>-\frac{6}{5}$

Step-by-step explanation:

Isolate the variable by dividing each side by factors that dont't contain the variable.

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2 years ago

PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198

Elena-2011 [213]

The weight in 1980 is $\frac{4k}{5}$ kilograms

Solution:

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

To find: weight in 1980

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

The percentage increase is given by formula:

$\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100$

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

Substituting the values in formula,

$25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}$

Thus the weight in kilograms in 1980 is $\frac{4k}{5}$

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3 years ago