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3 years ago

Please help This is due today! I will give crown to first correct answer!

Mathematics

2 answers:

CaHeK987 [17]3 years ago

7 0

2^2 + 4(2)-12=0 Hope that helps!

bonufazy [111]3 years ago

5 0

Answer:

Use the given functions to set up and simplify

f (2). 0

Step-by-step explanation:

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Pls help asapComplete the table using the function n = 9b + 19.

Aleksandr [31]

Answer:

−19

Step-by-step explanation:

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3 years ago

Ldodoskkdkdkdndkdnn gay yes

Sholpan [36]

Answer:

Uhh wut, but ok

Step-by-step explanation:

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3 years ago

If anyone can give me the answer that will be greatly appreciated :)

vfiekz [6]

42-x=58

or, -x=58-42

with change in side sign also chamges we change sides to make like terms in one side and unlike in amother side.

or, -x= 16

or,x=-16.

therefore x=-16...

Hope this helps you.

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3 years ago

At the local bakery Ariel bought 2 oatmeal cookies for $1.50. Mei bought 1/2 dozen oatmeal cookies for $4.50. Becky bought 8 oat

sergejj [24]

Answer:

Its proportional because when you divide each oatmeal bought and the amount you will end up with .75

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3 years ago

A product is made up of components A, B, C, D, E, F, G, H, I, and J. Components A, B, C, and F have a 1/10,000 chance of failure

lesantik [10]

Answer:

The overall reliability is 99.7402 %

Step-by-step explanation:

The overall reliability of the product is calculated as the product of the working probability of the components.

For components A,B,C and F we have :

$P(failure)=\frac{1}{10000}$

⇒

$P(Work)=1-\frac{1}{10000}=\frac{9999}{10000}=0.9999$

For components D,E,G and H we have :

$P(failure)=\frac{3}{10000}$

⇒

$P(Work)=1-\frac{3}{10000}=\frac{9997}{10000}=0.9997$

Finally, for components I and J :

$P(failure)=\frac{5}{10000}$

⇒

$P(Work)=1-\frac{5}{10000}=\frac{9995}{10000}=0.9995$

Now we multiply all the working probabilities. We mustn't forget that we have got ten components in this case :

Components A,B,C and F with a working probability of 0.9999

Components D,E,G and H with a working probability of 0.9997

Components I and J with a working probability of 0.9995

Overall reliability = $(0.9999)^{4}(0.9997)^{4}(0.9995)^{2}=0.997402$

0.997402 = 99.7402 %

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3 years ago