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Brums [2.3K]
2 years ago
11

Please help me. it is not a quiz a homework

Mathematics
1 answer:
OLga [1]2 years ago
7 0

Answer:

3rd graph

Step-by-step explanation:

3m ≥ 21   whenever you see '≤ or ≥' then you know the circle must be filled

divide each side by 3 to isolate 'm':

m ≥ 7  This inequality, when graphed, should have a closed circle on the number 7 and the shading would be to the right because the symbol is indicates all values "greater than" 7

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alexandr402 [8]

Answer: 1.5

Step-by-step explanation: Reverse the equation to get the answer.

-13 divided by 2 is -6.5

add 8 and you'll get 1.5

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8x^3 -5x^2 + 8x + 9+5x^3 + 3x^2 - 5x + 4 = 
8x^3+5x^3-5x^2 + 3x^2+ 8x - 5x+ 9<span>+ 4 = </span>
13x^3-2x^2+3x+13
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3 years ago
Can someone PLEASE help me solve this equation ? due soon
RideAnS [48]

\sf{Given : 3tanx + 7 = \dfrac{2}{(1 - sinx)(1 + sinx)}}

We know that : (a - b)(a + b) = a² - b²

\implies \sf{3tanx + 7 = \dfrac{2}{1 - sin^2x}}

We know that : 1 - sin²x = cos²x

\implies \sf{3tanx + 7 = \dfrac{2}{cos^2x}}

\sf{\bigstar \ \ We \ know \ that : \boxed{\sf{\dfrac{1}{cos^2x} = sec^2x}}}

\implies \sf{3tanx + 7 = 2sec^2x}

We know that : sec²x = 1 + tan²x

\implies \sf{3tanx + 7 =2(1 + tan^2x)}

\implies \sf{2 + 2tan^2x - 3 tanx - 7 = 0}

\implies \sf{2tan^2x - 3 tanx - 5 = 0}

\implies \sf{2tan^2x -  5tanx + 2tanx - 5 = 0}

\implies \sf{2tanx(tanx + 1) - 5(tanx + 1) = 0}

\implies \sf{(tanx + 1)(2tanx - 5) = 0}

\implies \sf{tanx = -1 \ (or) \ tanx = \dfrac{5}{2} }

8 0
3 years ago
ASAP PLS!! i attached a link with a screenshot of the question. please give step by step!!!!! will mark brainliest :)
emmainna [20.7K]

Answer:

I found two different solutions. Hope one of them help!

1. x = -1/3 = -0.333

2. x = 5/2 = 2.500

Step-by-step explanation:

13 ± √ 289

  x  =    ——————

                     12

Can  √ 289 be simplified ?

Yes!   The prime factorization of  289   is

  17•17

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 289   =  √ 17•17   =

               ±  17 • √ 1   =

               ±  17

So now we are looking at:

          x  =  ( 13 ± 17) / 12

Two real solutions:

x =(13+√289)/12=(13+17)/12= 2.500

or

x =(13-√289)/12=(13-17)/12= -0.333

Two solutions were found :

x = -1/3 = -0.333

x = 5/2 = 2.500

7 0
3 years ago
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He will have 250 dollars
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