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Brums [2.3K]
2 years ago
11

Please help me. it is not a quiz a homework

Mathematics
1 answer:
OLga [1]2 years ago
7 0

Answer:

3rd graph

Step-by-step explanation:

3m ≥ 21   whenever you see '≤ or ≥' then you know the circle must be filled

divide each side by 3 to isolate 'm':

m ≥ 7  This inequality, when graphed, should have a closed circle on the number 7 and the shading would be to the right because the symbol is indicates all values "greater than" 7

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1/4 divided by 5/6 = 1/a× b/c
motikmotik

Answer:

a= 24b/5c b= 5ac/24 c= 24b/5a

Step-by-step explanation:

Put the problem into a calculator that can solve with variables.

8 0
2 years ago
Endpoints of segment MN have coordinates (0, 0), (5, 1). The endpoints of segment AB have coordinates (1 1/2 , 2 1/4 ) and (−2 1
Zielflug [23.3K]

Answer:

k=21

Step-by-step explanation:

Find the slope of MN which is 1/5 (use the slope formula)

Use the slope formula for AB using k as y_2

Substitute and you get k=21

21-2.25/-2.25-1.5=-5

The lines are perpendicular because the slopes are the negative reciprocal of one another.

7 0
3 years ago
A local museum had a total of 38,627 vsitors last year. The museum was open everyday except for four holidays. On average how ma
sweet-ann [11.9K]

38,627/361 = 107.

107 people visit the museum every day according to the information given.

8 0
3 years ago
Read 2 more answers
What is the y-value of the point of intersection of y=2sinx-cosx and y=cosx over the interval 0≤x≤pi/2 ? a. 0 b. (square root of
horsena [70]
We have that

<span>y=2sinx-cosx
y=cosx
</span>over the interval 0≤x≤pi/2-------> 0≤x≤1.57

using a graph tool
see the attached figure

the solution in the given interval is the point (pi/4, 0.707)
the y-value of the point of intersection is 0.707 -----> √2/2

the answer is the option 
<span>b. (square root of 2)/2</span>

7 0
3 years ago
Read 2 more answers
What would x be?????
yarga [219]

Answer:

  12 cm

Step-by-step explanation:

The square of the length of the tangent segment is equal to the product of near and far distances to the circle from the point of intersection of the secant and tangent:

  (8 cm)^2 = (4 cm)(4 cm +x)

  16 cm = 4 cm +x . . . . . . divide by 4 cm

  12 cm = x . . . . . . . . . . . . subtract 4 cm

6 0
3 years ago
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