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Leni [432]
3 years ago
10

Solve for x cos x =sin 5x​

Mathematics
1 answer:
ira [324]3 years ago
3 0
The answer is going to be
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Need help please like I think I'm screwed
VLD [36.1K]
1hr 30 mins= 60mins+30mins=90mins
140$=90mins
In one minute, they make 140/90=14/9
in 9 hours=9*60mins=540mins
540*14/9=840
therefore,they make 840$ in 9 hours
5 0
3 years ago
Tu’s family stayed at a hotel for 10 nights on their vacation. The hotel charged a 10% room tax, per night. How much did they pa
Papessa [141]

Answer:

$200

Step-by-step explanation:

$2000 total divided by 10 nights= $200 per night

10% of $200 is $20

so $20 in taxes for 10 nights is 10*20= 200 for taxes

hope this helped plz mark brainliest trying to rank up :PP

4 0
3 years ago
A yellow ribbon is 56 centimeters long. It is twice as long as a green ribbon. A brown ribbon is four times as long as a green r
blsea [12.9K]

Answer:

The brown ribbon is 25,088 cm long.

Step-by-step explanation:

Yellow: 56 cm long

56 x 2= 112

Green: 112 cm long

112 x 2= 12544

12544 x 2= 25088

Brown: 25088 cm long

hope this helped ;)

3 0
3 years ago
Read 2 more answers
Fernando has been saving money to buy an e-book reader. A store has just marked down the price of its readers by 40%. Each reade
Amanda [17]

Answer:

$75

Step-by-step explanation:

Remove $25 from $150. (125)

Calculate 40% of 125. (50)

Remove that 40%. (75)

So...

150 - 25 = 125 - 50 = 75

3 0
3 years ago
Read 2 more answers
What’s the differential equation of
worty [1.4K]

Answer:

y=\frac{1}{x^{2}-6x+13 }

Step-by-step explanation:

We have given,

                        \frac{dy}{dx}=y^{2}(6-2x)

and initial condition x=3,\  y=\frac{1}{4}

Now,

\frac{dy}{dx}=y^{2}(6-2x)

Rearranging the variables, we get

\frac{dy}{y^{2} }=(6-2x).dx

Applying integration both sides, we get

\int\ {\frac{dy}{y^{2} } } \,=\int\ {(6-2x).} \, dx

⇒\frac{-1}{y} =6x-\frac{2x^{2} }{2}

⇒ \frac{-1}{y}=6x-x^{2}  +C                  

Putting the initial condition (i.e., x=3,\  y=\frac{1}{4}), we get

⇒ -4=6\times3-(3)^{2}+C

⇒ -4=18-9+C

∴ C=-13

We have,  \frac{-1}{y}=6x-x^{2}  +C    

now putting the value of C in above equation, we get

⇒ \frac{-1}{y}=6x-x^{2}  -13

⇒  \frac{1}{y}=-6x+x^{2}  +13

y=\frac{1}{x^{2}-6x+13 }

5 0
3 years ago
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