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iogann1982 [59]
2 years ago
9

Which triangle congruence shortcuts don't exist?

Mathematics
1 answer:
gogolik [260]2 years ago
7 0
OSSA
does not exist.
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Write the equation of the circle centered at (3, 5) and tangent to x = -1. I need help pleasse
Annette [7]

Answer:

(x - 3)² + (y - 5)² = 16

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r the radius

given (h, k ) = (3, 5 ) we require to find r

r is the distance from the centre to a point on the circle

given x = - 1 is a tangent the r is the distance between the x- coordinates

r = | 3 - (- 1) | = | 3 + 1 | = | 4 | = 4

then equation of circle is

(x - 3)² + (y - 5)² = 4² , that is

(x - 3)² + (y - 5)² = 16

7 0
2 years ago
Someone please explain how to do this problem? :)<br><br> Factor completely 2c5 + 44c4 + 242c3.
frez [133]
<span><span><span>2<span>c5</span></span>+<span>44<span>c4</span></span></span>+<span>242<span>c3</span></span></span><span><span><span>2<span>c5</span></span>+<span>44<span>c4</span></span></span>+<span>242<span>c3</span></span></span><span>=<span><span><span>2<span>c3</span></span><span>(<span>c+11</span>)</span></span><span>(<span>c+11</span><span>)</span></span></span></span>
8 0
3 years ago
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Convert the decimal to a fraction in simplest form. 0.0625
Fed [463]

Answer:

1/16

Step-by-step explanation:


5 0
3 years ago
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Which number is a solution of a² +4= 6a – 1?<br> 07<br> 6<br> 7<br> 8
LuckyWell [14K]

Answer:

a=1 or a=5

Step-by-step explanation:

a^{2}+4=6a−1

Step 1: Subtract 6a-1 from both sides.

a^{2}+4−(6a−1)=6a−1−(6a−1)

a^{2}−6a+5=0

Step 2: Factor left side of equation.

(a−1)(a−5)=0

Step 3: Set factors equal to 0.

a−1=0 or a−5=0

a=1 or a=5

(is it helpful rate me according to that

Thank You:-)

6 0
3 years ago
CAN SOMEONE HELP ME
Xelga [282]

Answer:

it should be number A hope that helps

7 0
3 years ago
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