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1 year ago

Find the common ratio of the geometric sequence 11, -55, 275,...11,−55,275,...

Mathematics

1 answer:

Kaylis [27]1 year ago

3 0

Answer:

r = -5

Step-by-step explanation:

common ratio (r) is found be dividing one term by its preceding term:

r = 275 ÷ -55 = -5

or, r = -55 ÷ 11 = -5

Therefore, r = -5

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Step-by-step explanation:

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1 year ago

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If parallelogram JKLM is rotated 270° counterclockwise around the origin, what are the coordinates of the endpoints of the side

Sati [7]

The <em>correct answer</em> is:

B) K’(6, 4); L’(3, 3)

Explanation:

A 270° clockwise rotation maps every point (x, y) to (y, -x). (It negates the x-coordinate and then switches it and the y-coordinate.)

This means the endpoints of the side congruent to KL, K' and L', would be mapped as:

K'(-4, 6)→(6, 4)

L'(-3, 3)→(3, 3)

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2 years ago

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what is the y-intercept of the line perpendicular to the line y=-3/4x+5 that includes the point (-3,-3)?

Deffense [45]

Answer:

Step-by-step explanation:

For this question, your friend is the point-slope form.

Point-slope form = $y-y_1 = m(x-x_1)$

The only variables you replace are m = slope, y1 = y of a given point, and x1 = x of a given point.

First, we need to find the slope that is perpendicular to the equation $y=-\frac{3}{4}x+5$

An equation that is perpendicular to another equation have to be negative reciprocals (negative inverse) of each other.

If the slope is 3, then the negative reciprocal of 3 is $-\frac{1}{3}$ .

So, since the given slope is -3/4, the negative reciprocal is $\frac{4}{3}$ .

We will use the negative reciprocal as m since we are trying to find the equation of line that includes (-3, -3) and is perpendicular to the other equation.

We will use point slope form using the (-3, -3) points and negative reciprocal as m.

$y-y_1 = m(x-x_1)\\y-(-3) = \frac{4}{3} (x-(-3))\\y+3=\frac{4}{3}(x+3)$

Now, we need to convert this into slope-intercept form. The reason why we need to do this is because y = mx + b, where b is the y-intercept. To do this, solve for y - or in other words, isolate y..

$y+3=\frac{4}{3}(x+3)\\y+3=\frac{4x}{3}+4\\y+3-3=\frac{4x}{3}+4-3\\y=\frac{4}{3}x+1$