This is an equation in STANDARD form for a circle:
(x-h)^2 + (y-k)^2 = r^2
The values of (h, k) are the center point of the circle. When they are put into an equation, their symbols flip as in, if they are positive on a graph, they become negative in the equation and vice versa.
The value (r) is the radius and is squared in the equation. In this case, the square root of 1 is 1.
(x)^2 + (y-6)^2 = 1
728x^2y^3 hope this helps
Answer:
No, They are not equivalent
Step-by-step explanation:
The two expressions are only said to be equivalent if they are the same regardless of whatever value the variable(s) is.
The variable in this question is x.
To prove this, we equate both expressions:
This shows that they have the same value ONLY when x is 1.
This is why Andre says that they are equivalent, but they are not.
False!
The first statement is correct, a company's traded shares reduces *BUT* that results in an increase in the par value or earnings per share. Same goes for a stock.
- Dysmy ☕
Answer:
a
Step-by-step explanation:
