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2 years ago

PLEASE HELP ASAP I WILL GIVE BRAINSLET TO THE CORRECT ANSWER!!!!!!!!!!

Mathematics

2 answers:

N76 [4]2 years ago

6 0

I THINK!!!!!! (x, y) = (-4, -25) im not completely sure tho

marta [7]2 years ago

5 0

Step-by-step explanation:

substitute y = 7x + 3 in equation 2

9x - 2y = 14

9x - 2(7x + 3) = 14

9x - 14x + 6 = 14

-5x + 6 = 14

-5x = 14 - 6

x = 8 ÷ 5

x = 1.6

subs x = 1.6 into equation 1

y = 7x + 3

y = 7(1.6) + 3

y = 11.2 + 3

y = 14.2

thus, x = 1.6, y = 14.2

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3 years ago

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2 years ago

A runner increases his velocity from 0 m/s to 20 m/s in 2.0 s. What was his average acceleration?

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2 years ago

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

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Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=5$ , we get,

$V=\frac{4}{3} (3.14)(125)$

$V=\frac{1580}{3}$

$V=523.3333 \ in^3$

Rounding off to two decimal places, we have,

$V=523.33 \ in^3$

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = $\frac{3}{4} (5)=3.75$

Radius of the third sphere = $\frac{3.75}{2} =1.875$

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=1.875$ , we get,

$V=\frac{4}{3} (3.14)(1.875)^3$

$V=\frac{4}{3} (3.14)(6.59)$

$V=27.5901 \ in^3$

Rounding off to two decimal places, we have,

$V=27.59 \ in^3$

Thus, the volume of the third sphere is 27.59 in³

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3 years ago

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Answer:

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3 years ago

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