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allsm [11]
2 years ago
7

Consider the following algorithms. Each algorithm operates on a list containing n elements, where n is a very large integer.

Computers and Technology
1 answer:
DochEvi [55]2 years ago
4 0

We have that the appropriate statement will be

  • An algorithm that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the algorithms run in reasonable time

III only.

Option B

From the question we are told

Consider the following <u>algorithms</u>. Each <u>algorithm</u> operates on a list containing n <em>elements</em>, where n is a very large <u>integer</u>.

I. An algorithm that accesses each <u>element</u> in the list twice.

II. An <em>algorithm </em>that accesses each <u>element </u>in the list n times.

III. An <u>algorithm</u> that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the <em>algorithms </em>run in <em>reasonable </em>time?

<h3>Algorithm  </h3>

Generally In order to get <em>admission </em>to every thing in the list twice, the algorithm has to traverse the listing twice,

which leads to 2*n entry to operations.

And if the every factor is accessed n times, the listing will be traversed n time, which leads to n^2 get right of entry to operations.

If n is a very giant <em>integer</em>, each 2*n and n^2 are plenty larger.

So, there will be <em>solely </em>ten entry to operations and this algorithm will have a sensible jogging time.

Therefore

An algorithm that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the algorithms run in reasonable time

III only.

Option B

For more information on  algorithm  visit

brainly.com/question/950632

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Lera25 [3.4K]
<h2>Solution :</h2>

The given problem is solved in Python.

def ComputeSquare():

side = float(input('Enter the side of the square: '))

if side > 0:

perimeter = 4 * side

area = side * side

print('Perimeter of the square is:',

perimeter, 'unit.')

print('Area of the square is:', area, 'square unit.')

<h3> else:</h3>

print('Invalid input.')

ComputeSquare()

<h2>Explanation :-</h2>

  • In this program, we create a function ComputeSquare() to calculate the perimeter and area of a square.

  • The function asks the user to enter the side of the square. The side is then stored in a variable.

  • Now, we check whether the side is greater than 0 or not using if-else statement.

  • If the condition is true, the perimeter and area is calculated which is displayed using print() statement.

  • If the condition is false, the else blocks executes printing the error message.

<h3>Refer to the attachment for output.</h3>

6 0
3 years ago
URGENT!
lutik1710 [3]

<u>Explanation:</u>

Hey there! you need not to panic about it ,your program didn't have Driver program i.e main program! the correct & working code is given below:

// C++ program to count  even digits  in a given number .

#include <iostream>  

using namespace std;  

// Function to count digits

int countEven(int n)  

{  

int even_count = 0;    

while (n > 0)  

{  

 int rem = n % 10;  

 if (rem % 2 == 0)  

  even_count++;  

 n = n / 10;  

}  

cout << "Even count : "

 << even_count;  

if (even_count % 2 == 0 )  

 return 1;  

else

 return 0;  

}  

// Driver Code  

int main()  

{  

int n;  

std::cin >>n;

int t = countEven(n);  

return 0;  

}  

6 0
3 years ago
You discover memory is corrupted, what would be an indication of a software vs. a hardware issue?
bearhunter [10]
Hey there!

Memory (RAM) is considered to be hardware since it is a physical component that makes up the computer and is accessed through the CPU rather than internal code that makes the computer run (which is software). Therefore, if you are having issues with the memory, it is likely a problem with a memory chip, making it a hardware issue. 

Hope this helped you out! :-)
8 0
3 years ago
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Answer:

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8 0
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Answer:

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  IMPLICIT  NONE

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  END IF

END PROGRAM  QuadraticEquationSolver

8 0
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