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Anastaziya [24]
3 years ago
11

Suppose that, even unrealistically, we are to search a list of 700 million items using Binary Search, Recursive (Algorithm 2.1).

What is the maximum number of comparisons that this algorithm must perform before finding a given item or concluding that it is not in the list
"Suppose that, in a divide-and-conquer algorithm, we always divide an instance of size n of a problem into n subinstances of size n/3, and the dividing and combining steps take linear time. Write a recurrence equation for the running time T(n), and solve this recurrence equation for T(n). Show your solution in order notation."

Computers and Technology
1 answer:
damaskus [11]3 years ago
7 0

Answer:

There is also an attachment below

Explanation:

Since we are talking about binary search, let's assume that the items are sorted according to some criteria.

Time complexity of binary search is O(logN) in worst case, best case and average case as well. That means it can search for an item in Log N time where N is size of the input. Here problem talks about the item not getting found. So, this is a worst case scenario. Even in this case, binary search runs in O(logN) time.

N = 700000000.

So, number of comparisions can be log(N) = 29.3 = 29.

So, in the worst case it does comparisions 29 times

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3 years ago
Which is the first calculating device invented?​
denis-greek [22]

Answer:the abacus

Explanation:

3 0
2 years ago
Read 2 more answers
A and B have same output or not? A B x=0 x=0 do do x<3 x=x+1 x=x+1 print x print x while x<3 while
katen-ka-za [31]

Answer:

A and B have different output:

A output will be 1

B output will be 123

Explanation:

A

X = 0

do x < 3

x = x+1

print x

while

B

X = 0

do x = x+ 1

print x

while x < 3

For statement A the condition statement which suppose to be after "while" is not set therefore the value of x will be printed.

For statement B the condition statement is set "x < 3" in front of "while" thereby result in iteration until the condition is false.

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4 years ago
A proper divisor of a positive integer $n$ is a positive integer $d &lt; n$ such that $d$ divides $n$ evenly, or alternatively i
juin [17]

Answer:

The program written in Python is as follows:

<em>See Explanation section for line by line explanation</em>

for n in range(100,1000):

     isum = 0

     for d in range(1,n):

           if n%d == 0:

                 isum += d

     if isum == n * 2:

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Explanation:

The program only considers 3 digit numbers. hence the range of n is from 100 to 999

for n in range(100,1000):

This line initializes sum to 0

     isum = 0

This line is an iteration that stands as the divisor

     for d in range(1,n):

This line checks if a number, d can evenly divide n

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If yes, the sum is updated

                 isum += d

This line checks if the current number n is a double-perfect number

     if isum == n * 2:

If yes, n is printed

           print(n)

<em>When the program is run, the displayed output is 120 and 672</em>

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What: A challenging question on this module's material.
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