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Anastasy [175]
3 years ago
9

What is the distance between (−8, 5) and (6, 5)? Enter your answer in the box.

Mathematics
1 answer:
Evgen [1.6K]3 years ago
6 0

Answer:

Step-by-step explanation:

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How do you solve this 8*[[(7+4)*2]-[(11-7)*4]]? I am trying to help my son with his homework and sad to say I am 46 and I can't
elena55 [62]

Answer: 160

Step-by-step explanation:

Don't know how to

7 0
3 years ago
What is the answer and work shown for 9r+r+7b+10+b+r+4n
ladessa [460]
Combine like terms
9r+r=10r^2
7b+b=8b^2
10+10r^2+8b^2+4n
7 0
3 years ago
Read 2 more answers
If f(x) = 5x − 3, which expression represents its inverse function?
tangare [24]

Answer:

f ^{-1}(x)=\frac{x+3}{5}

Step-by-step explanation:

To find the inverse of a function f (x) follow the steps below:

1) Make y = f (x)

y= 5x - 3

2) Solve for the variable x

y+3= 5x - 3+3

y+3= 5x

x=\frac{y+3}{5}

3) Exchange the variable x with the variable y

y=\frac{x+3}{5}

4) Make y = f ^{-1}(x)

f ^{-1}(x)=\frac{x+3}{5}

Finally, the inverse of the function f (x) is: f ^{-1}(x)=\frac{x+3}{5}

5 0
3 years ago
6.1.3
Nata [24]

Answer:

The requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

Step-by-step explanation:

A normal-distribution is an accurate symmetric-distribution of experimental data-values.  

If we create a histogram on data-values that are normally distributed, the figure of columns form a symmetrical bell shape.  

If X \sim N (µ, σ²), then Z=\frac{X-\mu}{\sigma}, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z \sim N (0, 1).

The distribution of these z-variates is known as the standard normal distribution.

Thus, the requirements that are necessary for a normal probability distribution to be a standard normal probability distribution are <em>µ</em> = 0 and <em>σ</em> = 1.

8 0
3 years ago
What is the area, in square centimeters, of the figure below? question 2 of 10
boyakko [2]

Answer:

area = 1/2× base×height

<u>1</u>×5.8×2.4

2

<u>1</u><u>3</u><u>.</u><u>9</u><u>2</u>

2

=6.96cm²

7 0
3 years ago
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