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2 years ago

Math Help Help Fast Alot of points

Mathematics

2 answers:

MrMuchimi2 years ago

8 0

Here mark the angles

m<FHG=75
m<FGH=55
m<GHI=59°
m<GIH=63°

By using angle sum property

m<IGH=180-122=58

m<FGH < m<IGH <m<GHI <m<GIH <m <FHG

FH<IH<GI<GH<FG

salantis [7]2 years ago

4 0

Answer:

IH < GI < GH < FH < FG

Step-by-step explanation:

<u>Find missing angles</u>

Sum of interior angles of a triangle = 180°

⇒ ∠GFH = 180 - 55 - 75 = 50°

⇒ ∠IGH = 180 - 59 - 63 = 58°

<u>Side lengths in relation to interior angles</u>

The longest side of a triangle is opposite the largest interior angle, and the shortest side is opposite the smallest angle.

Therefore, angles/sides in order of least to greatest:

ΔIGH

∠IGH = 58 → its opposite side is IH

∠GHI = 59 → its opposite side is GI

∠G|H = 63 → its opposite side is GH

Therefore, IH < GI < GH

ΔFGH

∠GFH = 50 → its opposite side is GH

∠FGH = 55 → its opposite side is FH

∠FHG = 75 → its opposite side is FG

Therefore, GH < FH < FG

Combining: IH < GI < GH < FH < FG

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Pls help me with my math

natka813 [3]

Answer:

Step-by-step explanation:

Left line is defined when x < 1 (x is less than 1). The point is not full and that means that x = 1 is not included.

Right line is defined when x is greater or equal to one x ≥ 1.

Options that have x < 1 and x ≥ 1 are b and d, so the answer is one of those.

Equations of the lines are in slope-intercept form y = mx + b, where m is slope and b is y-intercept.

Right line has steeper slope than left line, so the slope of right line will have bigger absolute value. That is the case with option d. (Left line has slope -1 and right one has slope -2, absolute value of right slope is bigger.)

You could also check with y-intercepts. Left line has y-intercept at y = 2 and left line is defined when x < 1. Only option d meets these conditions.

4 0

1 year ago

The plane x + y + z = 12 intersects paraboloid z = x^2 + y^2 in an ellipse.(a) Find the highest and the lowest points on the ell

emmasim [6.3K]

Answer:

Highest (-3,-3)

Lowest (2,2)

Farthest (-3,-3)

Closest (2,2)

Step-by-step explanation:

To solve this problem we will be using Lagrange multipliers.

Let us find out first the restriction, which is the projection of the intersection on the XY-plane.

From x+y+z=12 we get z=12-x-y and replace this in the equation of the paraboloid:

$\bf 12-x-y=x^2+y^2\Rightarrow x^2+y^2+x+y=12$

completing the squares:

$\bf x^2+y^2+x+y=12\Rightarrow (x+1/2)^2-1/4+(y+1/2)^2-1/4=12\Rightarrow\\\\\Rightarrow (x+1/2)^2+(y+1/2)^2=12+1/2\Rightarrow (x+1/2)^2+(y+1/2)^2=25/2$

and we want the maximum and minimum of the paraboloid when (x,y) varies on the circumference we just found. That is, we want the maximum and minimum of

$\bf f(x,y)=x^2+y^2$

subject to the constraint

$\bf g(x,y)=(x+1/2)^2+(y+1/2)^2-25/2=0$

Now we have

$\bf \nabla f=(\displaystyle\frac{\partial f}{\partial x},\displaystyle\frac{\partial f}{\partial y})=(2x,2y)\\\\\nabla g=(\displaystyle\frac{\partial g}{\partial x},\displaystyle\frac{\partial g}{\partial y})=(2x+1,2y+1)$

Let $\bf \lambda$ be the Lagrange multiplier.

The maximum and minimum must occur at points where

$\bf \nabla f=\lambda\nabla g$

that is,

$\bf (2x,2y)=\lambda(2x+1,2y+1)\Rightarrow 2x=\lambda (2x+1)\;,2y=\lambda (2y+1)$

we can assume (x,y)≠ (-1/2, -1/2) since that point is not in the restriction, so

$\bf \lambda=\displaystyle\frac{2x}{(2x+1)} \;,\lambda=\displaystyle\frac{2y}{(2y+1)}\Rightarrow \displaystyle\frac{2x}{(2x+1)}=\displaystyle\frac{2y}{(2y+1)}\Rightarrow\\\\\Rightarrow 2x(2y+1)=2y(2x+1)\Rightarrow 4xy+2x=4xy+2y\Rightarrow\\\\\Rightarrow x=y$

Replacing in the constraint

$\bf (x+1/2)^2+(x+1/2)^2-25/2=0\Rightarrow (x+1/2)^2=25/4\Rightarrow\\\\\Rightarrow |x+1/2|=5/2$

from this we get

and the candidates for maximum and minimum are (2,2) and (-3,-3).

Replacing these values in f, we see that

f(-3,-3) = 9+9 = 18 is the maximum and

f(2,2) = 4+4 = 8 is the minimum

Since the square of the distance from any given point (x,y) on the paraboloid to (0,0) is f(x,y) itself, the maximum and minimum of the distance are reached at the points we just found.

We have then,

(-3,-3) is the farthest from the origin

(2,2) is the closest to the origin.

3 0

3 years ago

Express 8 inches as a fraction of 3 feet in lowest terms

ArbitrLikvidat [17]

3 ft* 12 inches in a ft= 36 inches total

8/36= 2/9

Final answer: 2/9

7 0

3 years ago

Read 2 more answers

Vesna [10]