Basing on the description, a parabola opening up with vertex at origin, the formula with vertex at origin is used, x^2 = 4py. p is the focus and so with the dimensions given, we obtain a 0.25 and that is the distance of the focus to the vertex.
The integers are x, x + 2 and x + 4
x + x + 2 + x + 4 = 36
3x + 6 = 72
3x = 36 - 6 = 30
x = 30/3 = 10
The least numbers is 10
Therefore, the numbers are 10, 12 and 14
Answer:
2a(b^3 - 7b + 8)
Step-by-step explanation:
I'm assuming that 2a2b3 is 2a2b^2. If not, this answer isn't correct.
Look at the whole numbers. Is there a number that divides into them evenly? Yes, 2, so you pull 2 from the problem and divide each number by 2. Do the same for each variable.
2a2b3 - 14ab + 16a
2(ab^3 - 7ab +8a)
2a(b^3 - 7b + 8)
