Answer:
x=0, x= - 3, x=9
Step-by-step explanation:
f(x)=7/2x(x+3)(x-9)
f(x) doesn't exist for x=0,-3,9
as

vertical asymptote:
x=0, x= - 3, x=9
<span>First rewrite y - 2x<span> 2</span> = 8 x + 5 as</span>
y = 2x<span> 2</span><span> + 8 x + 5 </span>
Complete square and determine vertex.
y = 2(x<span> 2</span><span> + 4x + 4) - 8 + 5 </span>
= 2(x + 2)<span> 2</span><span> - 3 </span>
<span>vertex at (- 2 , - 3) </span>
If parabola is translated 3 units to the left and 2 units up its vertex is also translated 3 units to the right and 2 units up .
<span>vertex after translations is at: (-2 - 3 , - 3 + 2) = (-5 , -1)</span>
For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

Where:
m: It's the slope
b: It is the cutoff point with the y axis
We find the slope with the given points:

Thus, the line is given by:

We substitute a point to find "b":

Finally, the equation is:

Answer:

BEHJEJEBEHRUUE what is this eheujrf
Total surface area = 2 * circular base + circumference * height
= 2 * pi*(4)^2 + 8pi * 12
= 32pi + 96pi
= 128pi answer