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guapka [62]
3 years ago
11

Which polynomial is prime? x2 – 36 x2 16 x2 – 7x 12 x2 – x – 20.

Mathematics
1 answer:
miskamm [114]3 years ago
5 0

Answer:

start with what you know

Step-by-step explanation:

makes you smarter

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Hey yall please help me I suffer from short time memory loss and it's hard for me to focus and remember Find the distance betwee
podryga [215]

Answer:

The distance between 2 points on a graph is given as:

root over of ((x2-x1)^2 + (y2-y1)^2)

using this formula we have,

root over of ((5-(-3))^2 + (1-(-4))^2

=root over of (64+25)= 9.43

Ans: the distance between A and b is 9.43 units.

3 0
3 years ago
Express y in terms of x.
enyata [817]

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3 years ago
84 divided 5,376 ? (Show work)
DIA [1.3K]

Answer:

64

Step-by-step explanation:

  6 4

8 4 5 3 7 6  

- 5 0 4

3 3 6

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0

5 0
3 years ago
My guys can yall help with this
Oksanka [162]

Answer:

2nd one I just did the math

3 0
4 years ago
I’m having trouble with this problem. Please help
iVinArrow [24]

The software rendering this question really butchered it... I think it's saying the displacement vector for the particle is

\vec r(t) = \sin(t) \, \vec\imath + 4t^3 \, \vec\jmath + 5t \, \vec k

Differentiate twice with respect to time t to get the velocity and acceleration vectors, respectively:

\dfrac{d\vec r}{dt} = \vec v(t) = \cos(t) \,\vec\imath + 12t^2 \,\vec\jmath + 5 \,\vec k

\dfrac{d^2\vec r}{dt^2} = \dfrac{d\vec v}{dt} = \vec a(t) = -\sin(t) \,\vec\imath + 24t \,\vec\jmath

Then at t=3, the acceleration of the particle is

\vec a(3) = -\sin(3)\,\vec\imath + 72\,\vec\jmath

which most closely resembles the first choice.

4 0
2 years ago
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