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3 years ago

What is the percent of increase in the rent for Bob's apartment if it went from $560 to $616?

Mathematics

2 answers:

son4ous [18]3 years ago

5 0

This is a two step problem. First, you need to find the difference (or increase) in the rent using subtraction.

616-560 = $56 increase

Now we need to figure what percent 56 is to the original amount (560)

We voice it like this:

56 is to 560 as x is to 100.

The equation looks like this:

56/560 - x/100

Cross multiply to cancel out the denominators.

56 x 100 = 560 x

5600 = 560 x

x = 10 percent.

Check it!

What is 10 percent of 560?

560 x .1 = $56

Was that your increase? ... yes.

Svetlanka [38]3 years ago

4 0

Answer:

10%

Step-by-step explanation:

Apply the formula for percent increase: 616-560/560 * 100 = 56/560*100=10%... ALL CREDIT GOES TO AOPS

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Khan Academy.

Step-by-step explanation:

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2 years ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

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3 years ago

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kipiarov [429]

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3 years ago

Find the value of x if the arithmetic mean of 3 and 3x+5 is 8?

mina [271]

Answer:

Step-by-step explanation:

3x+5=8

Group like terms

3x=8-5

3x=3

Divide both side by the co-efficient of x which is 3

3x/3=3/3

x=1

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2 years ago