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Novay_Z [31]
3 years ago
9

Question A low level distributed denial of service (DDoS) attack that involves SYN or SYN/ACK flooding describes what type of at

tack
Computers and Technology
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer:

TCP SYN flood

Explanation:

TCP SYN flood (a.k.a. SYN flood) is a type of Distributed Denial of Service (DDoS) attack that exploits part of the normal TCP three-way handshake to consume resources on the targeted server and render it unresponsive.

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Write a statement that outputs variable numObjects. End with a newline.
dalvyx [7]

Answer:

The code is witten in Java and given in the explanation section.

Using a Scanner object we receive a the user's input and with the System.out.println we output the variable

Explanation:

import java.util.Scanner;

public class VariableOutput{

   public static void main (String [] args){

       Scanner input = new Scanner(System.in);

       System.out.println("Enter an Integer 15 or 40");

       int numObjects = input.nextInt();

       System.out.println("You entered the number "+numObjects);

   }

}

7 0
3 years ago
The chip that controls the radio frequency waves within a device
torisob [31]

Answer:

An RF module

Explanation:

I googled it lol

7 0
4 years ago
Describe the Order of Operations in Java programming.
cestrela7 [59]

Answer:

It stands for Parentheses, Exponents, Multiplication/Division, Addition/Subtraction. PEMDAS is often expanded to the mnemonic "Please Excuse My Dear Aunt Sally" in schools. Canada and New Zealand use BEDMAS, standing for Brackets, Exponents, Division/Multiplication, Addition/Subtraction.

5 0
3 years ago
1) Create a recursive program that prompts the user for a nonnegative integer N and outputs. a) Sum [N] b) BiPower [N] c) TimesF
Georgia [21]

Answer:

//Code is created using java

import java.util.*;

// returns the sum

public int sum(int N)

{

if(N==1)

return (1);

else

return N+sum(N-1);

}

// code to return the Bipower ouput

public int BiPower(int N)

{

if(N==1)

return (2);

else

return 2*BiPower(N-1);

}

// Code to return TimesFive output

public int TimesFive(int N)

{

if(N==1)

return 5;

else

return 5 + timesFive(N-1);

}

public static void main(String args[])

   {

//Prompts the user to enter a nonnegative integer

       int N  = Integer.parseInt.(console.readLine("Enter a nonnegative integer:  "));

//Outputs the sum, Bipower and TimesFive

       System.out.println(sum(n));

       System.out.println(BiPower(n));  

       System.out.println(TimesFive(n));

   }

}

4 0
3 years ago
Write a program that dynamically allocates an array large enough to hold a user-defined number of test scores. Once all the scor
Anastasy [175]

Answer:

// Program written in C++

// Comments are used to explain some lines

#include <iostream>

#include <iomanip>

using namespace std;

// Functions

void getData(double *, int);

void selectionSort(double *, int);

double getAverage(double *, int);

void displayData(double *, int, double);

int main() //Main Method

{

double *ToTest, // To dynamically allocate an array

Average; // To hold the average of the scores

int Scores; // To hold number of scores

// Get number of scores

cout << "Number of average to find? ";

cin >> Scores;

// Allocate an array to number of scores

ToTest = new double[Scores];

getData(ToTest, Scores);

selectionSort(ToTest, Scores);

Average = getAverage(ToTest, Scores);

printData(ToTest, Scores, Average);

return 0;

}

//Get Data

void getData(double *ToTest, int Scores)

{

cout << "Enter each scores.\n";

for (int i = 0; i < Scores; i++)

{

do

{

cout << "Score #" << (i + 1) << ": ";

cin >> *(ToTest + i);

if (*(ToTest + i) < 0)

{

cout << "Scores must be greater than 0.\n"

<< "Re-enter ";

}

} while (*(Test + i) < 0);

}

}

// Selection Sort

void selectionSort(double *ToTest, int Scores)

{

int startscan, minIndex;

double minValue;

for (startscan = 0; startscan < (Scores - 1); startscan++)

{

minIndex = startscan;

minValue = *(ToTest + startscan);

for (int i = startscan + 1; i < Scores; i++)

{

if (*(ToTest + i) < minValue)

{

minValue = *(Test + i);

minIndex = i;

}

}

*(ToTest + minIndex) = *(ToTest + startscan);

*(ToTest + startscan) = minValue;

}

}

// Calculate Average

double getAverage(double *ToTest, int Scores)

{

double Total;

for (int i = 0; i < Scores; i++)

{

Total += *(ToTest + i);

}

return Total / Scores;

}

// Print Data

void printData(double *ToTest, int Scores, double Avg)

{

cout << "\n Test scores\n";

cout << "Number of scores: " << Scores << endl;

cout << "Scores in ascending-order:\n";

for (int i = 0; i < Scores; i++)

{

cout << "#" << (i + 1) << ": " << *(ToTest + i) << endl;

}

cout << fixed << showpoint << setprecision(2);

cout << "Average score: " << Avg << endl;

}

6 0
3 years ago
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