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2 years ago

8

Ye Li drew a quadrilateral that is both a rectangle and a rhombus. Name the quadrilateral and describe it using the properties o

f sides and angles.
(please keep the explanation simple)

1 answer:

IRISSAK [1]2 years ago

3 0

Answer:

Ye Li drew a scalene triangle. A scalene triangle is where all side measure and all angle measure are different.

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What is the simplified form of (12-4t)/(t^2-2t-3)? State any excluded values

nexus9112 [7]

Answer:

<em>Solution; - 4 / t + 1</em>

Step-by-step explanation:

See procedure below;

( 12 - 4t ) / ( t^2 - 2t - 3 ) ⇒ Factor out common term - 4 in 12 - 4t,

- 4 * ( t - 3 ) / ( t^2 - 2t - 3 ) ⇒ Break bottom expression into groups,

- 4 * ( t - 3 ) / ( t^2 + t ) + ( - 3t - 3 ) ⇒ Factor out t from t^2 + t,

- 4 * ( t - 3 ) / t * ( t + 1 ) + ( - 3t - 3 ) ⇒ Factor out - 3 from - 3t - 3,

- 4 * ( t - 3 ) / t * ( t + 1 ) + ( - 3 * ( t + 1 ) ) ⇒ Factor out common term t + 1,

- 4 * ( t - 3 ) / ( t + 1 ) * ( t - 3 ) ⇒ Cancel out like term t - 3,

<em>Solution; - 4 / t + 1</em>

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3 years ago

How to solve x+7=3<br> In one step equations

rodikova [14]

<span>Subtract 7 from both sides of the equation. Check: Substitute -4 for x in the original equation. If, after the substitution, the left side equals the right side, your answer is correct. ( -4 ) + 7 = 3 </span>

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3 years ago

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What is the slope of the line described by the equation below

Y_Kistochka [10]

Y-5 = 6x-24 ad 5 to both sides to get y alone
y=6x-19 the slope of the line is 6 and the y-intercept is -19 or (0,-19)
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4 years ago

Solve the radical equation. square root 6n-11= n – 3 Which solution is extraneous? A.)2

Anvisha [2.4K]

ANSWER

D) 10

EXPLANATION

We want to solve the radical equation,

$\sqrt{6n - 11} = n - 3$

Square both sides,

$6n - 11 = (n - 3) ^{2}$

Expand brackets on right hand side,

$6n - 11 = {n}^{2} - 6n + 9$

Rewrite in general quadratic equation form,

${n}^{2} - 12n + 20 = 0$

Factor to obtain,

$(n - 2)(n - 10) = 0$

Apply the zero product principle to get,

$n = 2 \: or \: n = 10$

We put n=2 into the equation to get,

$\sqrt{6(2) - 11} = 2 - 3$

$1 = - 1$

This statement is false, hence 2 is an extraneous solution

We put n=10, to get

$\sqrt{6(10) - 11} = 10 - 3$

$\sqrt{49} = 7$

$7 = 7$

This is true, hence the only solution is
$n = 10$

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4 years ago

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What is the largest number below 10

max2010maxim [7]

Answer:

9

Step-by-step explanation:

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3 years ago