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svetoff [14.1K]
3 years ago
11

What is the relationship between the mind and the body?

Advanced Placement (AP)
1 answer:
Rom4ik [11]3 years ago
6 0
The answer is C. This is because the mind can make the body do anything, and the body can make the brain think certain things also. So basically the mind and the body play tag with each other on this topic.
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Which of hubbie’s findings supported the Big Bang theory? Check all that apply
poizon [28]

Answer:

  1. There are billions of galaxies in the universe, not just one.
  2. The universe formed from a central point.
  3. Most galaxies in the universe are moving away from Earth.

Explanation:

  • Hubble's theory is a model of the observable universe and represents the earliest form of evolution of the universe in the form of a big bang. The process of large-scale evolution and origin and growth of the universe.
  • It explains the development of the universe from an ingle bang where all the galaxies spread and are still growing further apart from each other.
  • It explains the formation of the university from a single point in the history of time. It also explains the formation of galaxies in the universe such as those of the spiral and elliptical ones. How the galaxies and planets came into the formation from this one single point.
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3 years ago
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Aleksandr [31]
5 presidentes los ultimos 5 años
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2 years ago
I can’t figure this problem out
Natalka [10]

Answer:

Explanation:

Alright so the way to do this is to use properties of integrals to make our life easier.

So we have:

\int\limits^4_1 {(3f(x)+2)} \, dx

So lets break this up into two different integrals that represent the same area.

\int\limits^4_0 {f(x)} \, dx - \int\limits^1_0 {f(x)} \, dx = \int\limits^4_1 {f(x)} \, dx

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

\int\limits^4_1 {f(x)} \, dx

But since we have these values we can say that:

-3 - 2 = -5

Which means that \int\limits^4_1 {f(x)} \, dx = -5

So now we can evaluate \int\limits^4_1 {(3f(x)+2)} \, dx

Lets first break up our integrand into two integrals

\int\limits^4_1 {(3f(x)+2)} \, dx = 3\int\limits^4_1{f(x)} \, dx + 2\int\limits^4_1 {} \, dx

Now we can evaluate this:

We know that \int\limits^4_1 {f(x)} \, dx = -5

So:

3(-5)+2[x] where x is evaluated at 4 to 1 so

-15 + 2(3)

So we are left with -15 + 6 = -9

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