Find the area of a regular octagon with apothem k and side of 10
1 answer:
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Answer:
y - 11 = - 3(x + 2)
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) is a point on the line
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, 5) and (x₂, y₂ ) = (- 2, 11)
m = =
= - 3
Use either of the 2 given points for (a, b)
Using (a, b) = (- 2, 11), then
y - 11 = - 3(x - (- 2)), that is
y - 11 = - 3(x + 2)