Question

You have 6,368 grams of a radioactive kind of cobalt. If its half-life is 271 days, how much

Answer 1

$\textit{Amount for Exponential Decay using Half-Life} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{current amount}\\ P=\textit{initial amount}\dotfill &6368\\ t=\textit{elapsed time}\dotfill &542\\ h=\textit{half-life}\dotfill &271 \end{cases} \\\\\\ A=6368\left( \frac{1}{2} \right)^{\frac{542}{271}}\implies A=6368\left( \frac{1}{2} \right)^2\implies A=1592$