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r-ruslan [8.4K]
2 years ago
10

Quadrilateral PQRS is a rhombus. Find the value of y

Mathematics
1 answer:
White raven [17]2 years ago
7 0

Answer:

3

Step-by-step explanation:

set the two equations equal to each other

2y+3 = 5y-6

add 6 to both sides

subtract 2y from both sides

9=3y

divide both sides by 3

y=3

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Find the nth Maclaurin polynomial for the function. f(x) = sec(x), n = 2 P_2(x) =
Alika [10]

Answer:

\mathbf{P_2(x) = 1+\dfrac{x^2}{2}}

Step-by-step explanation:

Given that:

f(x) = sec (x)  , n = 2

Where are to find P_2(x)

Suppose ; f(x) = sec (x)  , n = 2

then

f(0) = sec (0) = 1

f'(x) = sec (x)* tan (x)|_{x=0} = 0

f''(x) = sec (x)*tan ^2(x)+ sec (x) * sec^2(x)

f''(x) = sec (x)*tan ^2(x)|_{x=0} + sec^3(x)

f''(x) = 0 + sec^3(0)

f''(x) = 1

f(x) = f(0) + \dfrac{f'(0)x}{1!}+ \dfrac{f''(0)x^2}{2!}+  \dfrac{f'''(0)x^3}{3!}+...

f(x) = 1 + \dfrac{0}{1!}x+ \dfrac{x^2}{2!}+...

f(x) = 1 + \dfrac{x^2}{2}+...

since order n =2

\mathbf{P_2(x) = 1+\dfrac{x^2}{2}}

8 0
3 years ago
Complete the factored form,<br> 46x + 9x-2-(15%-2))
VladimirAG [237]

Answer:55x+

−3

20

Step-by-step explanation:

3 0
4 years ago
Geo question
yanalaym [24]
I’m pretty sure your answer is B

if the sides of a square aren’t congruent then it’s not actually a square

hope this helps:)
brainliest?
4 0
3 years ago
Subtract 9a^2-6a+59a 2 −6a+59, a, squared, minus, 6, a, plus, 5 from 10a^2+3a+2510a 2 +3a+2510, a, squared, plus, 3, a, plus, 25
nasty-shy [4]

Answer:

The answer to your question is   a² + 9a + 20

Step-by-step explanation:

               10a² + 3a + 25 - (9a² - 6a + 5)

- Remove parentheses changing the sign of the second polynomial

               10a² + 3a + 25 - 9a² + 6a - 5

- Group like terms

               (10a² - 9a²) + (3a + 6a) + (25 - 5)

- Simplify and result

                a² + 9a + 20

8 0
3 years ago
Divide -20.40 and -4
MaRussiya [10]
-20.40 divided by 4 equals 5.1
3 0
3 years ago
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