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Sonja [21]
2 years ago
9

Solve equation by using the quadratic formula.

Mathematics
1 answer:
Sati [7]2 years ago
5 0

Answer: 1:  x=3, x=1

2:  x= -5

3:  There are 2 real solutions.

4:  There are 2 real solutions.

5:  There are no real solutions.

6.  There is 1 real solution.

7.  

8.  x= -6, x = -2

9.  x = -1/6, x=1

10.  

Explanation:

1.  The quadratic formula is

Substituting our known information we have:

2.  Rewriting the quadratic in standard form we have x²+10x-25=0. Substituting this into the quadratic formula gives us:

3.  The discriminant is b²-4ac.  For this problem, that is 20²-4(-4)(25)=400--400=800.  Since this is greater than 0, there are 2 real solutions.

4.  The discriminant in this problem is 7²-4(2)(-15)=49--120=49+120=169.  This is greater than 0, so there are 2 real solutions.

5.  The discriminant in this problem is 1²-4(-2)(-28)=1-224=-223.  Since this is less than 0, there are no real solutions.

6.  If the discriminant of a quadratic is 0, then by definition there is 1 real solution.

7.  Rewriting the quadratic we have 3x²-4x-2=0.  Using the quadratic formula we have:

8.  Factoring this trinomial we want factors of 12 that sum to 8.  6*2 = 12 and 6+2=8, so those are our factors.  This gives us:

(x+6)(x+2)=0

Using the zero product property we know that either x+6=0 or x+2=0.  Solving these equations we get x= -6 or x= -2.

9.  Factoring this trinomial we want factors of 6(-1)=-6 that sum to -5.  (-6)(1)=-6 and -6+1=-5, so this is how we "split up" the x term:

6x²-6x+1x-1=0

We group together the first two and the last two terms:

(6x²-6x)+(1x-1)=0

Factor the GCF out of each group.  In the first group, that is 6x:

6x(x-1)+(1x-1)=0

In the second group, the GCF is 1:

6x(x-1)+1(x-1)=0

Both terms have a factor of (x-1), so we can factor it out:

(x-1)(6x+1)=0

Using the zero product property, we know either x-1=0 or 6x+1=0.  Solving these equations we get x=1 or x=-1/6.

10.  Substituting our information into the quadratic formula we get:

Step-by-step explanation:

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3 years ago
The information below explains the transformations and translations of a logarithmic function. What is the equation for this fun
maks197457 [2]

The transformed function is y = 1/3(log(x/3 + 4)) + 1

<h3>How to transform the logarithmic function?</h3>

The parent logarithmic function is

y = log(x)

When shifted left by 4 units, we have:

y = log(x + 4)

When shifted up by 3 units, we have:

y = log(x + 4) + 3

When compressed vertically by 1/3, we have:

y = 1/3(log(x + 4) + 3)

This gives

y = 1/3(log(x + 4)) + 1

When stretched horizontally by 3, we have:

y = 1/3(log(x/3 + 4)) + 1

Hence, the transformed function is y = 1/3(log(x/3 + 4)) + 1

<h3>The transformation of function f(x)</h3>

We have:

f(x) = log[-(x – 5)] + 4

Set the radicand greater than 0

-(x - 5) > 0

Divide by -1

x - 5 < 0

Add 5 to both sides

x < 5 -- this represents the domain

A logarithmic function can output any real number.

So, the range is -\infty < f(x) < \infty

In the domain, we have:

x < 5

This means that the interval of decrease is -\infty < x < 5

Rewrite as an equation

x = 5 --- this represents the equation of asymptote

Read more about logarithmic functions at:

brainly.com/question/12708344

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6 0
1 year ago
Write the cubic polynomial function f(x)in expanded form with zeros −6,−5,and −1, given that f(0)=60
RSB [31]

Answer:

f(x)=2x^{3}+24x^{2}+82x+60

Step-by-step explanation:

we know that

The roots of the polynomial are the values of x when the value of the polynomial f(x) is equal to zero

The roots of the polynomial function are

x=-6 -----> (x+6)=0

x=-5 -----> (x+5)=0

x=-1 -----> (x+1)=0

The equation of the cubic polynomial is

f(x)=a(x+6)(x+5)(x+1)

where

a is the leading coefficient

Remember that

f(0)=60

That means ------> For x=0 the value of f(x) is equal to 60

substitute the value of x and the value of y in the function and solve for a

60=a(0+6)(0+5)(0+1)

60=a(6)(5)(1)

60=30a

a=2

so

f(x)=2(x+6)(x+5)(x+1)

Applying the distributive property

Convert to expanded form                  

f(x)=2(x+6)(x+5)(x+1)\\\\f(x)=2(x+6)(x^{2}+x+5x+5)\\\\f(x)=2(x+6)(x^{2}+6x+5)\\\\f(x)=2(x^{3}+6x^{2}+5x+6x^{2}+36x+30)\\\\f(x)=2x^{3}+24x^{2}+82x+60

3 0
3 years ago
Find the equation of the line specified. The slope is -7, and it passes through ( 5, -3).
Montano1993 [528]
The general equation of a line is
y= ax + b
where a is the slope
So a = -7
So y= -7x + b
But it passes through the point (5, -3)
Substitute the coordinates to calculate b:
So -3 = -7(5) + b
-3 = -35 + b
b= 35-3
b= 32
So the equation of the line of slope -7 and passing through the point (5, -3) is
y= -7x + 32
7 0
3 years ago
Read 2 more answers
ANSWER PLZ QUICK AND FAST
Sergeu [11.5K]

its a. numerical expression.

4 0
2 years ago
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