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2 years ago

What type of agriculture was practiced in new england?.

SAT

1 answer:

Anon25 [30]2 years ago

7 0

Answer:

The New England colonies had rocky soil, which was not suited to plantation farming, so the New England colonies depended on fishing, lumbering, and subsistence farming.

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company manufactured six television sets on a given day, and these TV sets were inspected for being good or defective. The resul

lana [24]

Sampling distribution involves the proportions of a data element in a given sample.

<em>The proportion of Good TV set is 0.67</em>
<em>The number of ways of selecting 5 from 6 TV sets is 6</em>
<em>The number of ways of selecting 4 from 6 TV sets is 15</em>

<em />

Given

$n = 6$

Sample Space = Good, Good, Defective, Defective, Good, Good

<u>(a) Proportion that are good</u>

From the sample space, we have:

$Good = 4$

So, the proportion (p) that are good are:

$p = \frac{Good}{n}$

$p = \frac{4}{6}$

$p = 0.67$

<u>(b) Ways to select 5 samples (without replacement)</u>

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 5$

So, we have:

$^6C_5 = \frac{6!}{(6 - 5)!5!}$

$^6C_5 = \frac{6!}{1!5!}$

$^6C_5 = \frac{6 \times 5!}{1 \times 5!}$

$^6C_5 = \frac{6}{1}$

$^6C_5 = 6$

Hence, there are 6 ways

<u>(c) All possible sample space of 4</u>

First, we calculate the number of ways to select 4.

This is calculated using:

$^nC_r = \frac{n!}{(n - r)!r!}$

Where

$r = 4$

So, we have:

$^6C_4 = \frac{6!}{(6 - 4)!4!}$

$^6C_4 = \frac{6!}{2!4!}$

$^6C_4 = \frac{6 \times 5 \times 4}{2 \times 1 \times 4!}$

$^6C_4 = \frac{30}{2}$

$^6C_4 = 15$

So, the table is as follows:

$\left[\begin{array}{ccc}TV&Good&Proportion\\1,2,3,4&2&0.5&2,3,4,5&2&0.5&3,4,5,6&2&0.5\\4,5,6,1&3&0.75&5,6,1,2&4&1&6,1,2,3&3&0.75\\1,2,3,5&3&0.75&3,5,6,2&3&0.75&1,3,4,5&2&0.5\\1,3,4,6&2&0.5&1,4,5,2&3&0.75&2,4,6,1&3&0.75\\2,4,6,3&2&0.5&2,4,6,5&3&0.75&3,5,6,1&3&0.75\end{array}\right]$

The proportion column is calculated by dividing the number of Good TVs by the total selected (4) i.e.

$p = \frac{Good}{n}$

<u>(d) The sampling distribution</u>

In (a), we have:

$p = 0.67$ --- proportion of Good TV

The sampling error is calculated as follows:

$SE_n = |p - p_n|$

So, we have:

$\left[\begin{array}{ccc}TV&Good&SE\\1,2,3,4&2&0.17&2,3,4,5&2&0.17&3,4,5,6&2&0.17\\4,5,6,1&3&0.08&5,6,1,2&4&0.33&6,1,2,3&3&0.08\\1,2,3,5&3&0.08&3,5,6,2&3&0.08&1,3,4,5&2&0.17\\1,3,4,6&2&0.17&1,4,5,2&3&0.08&2,4,6,1&3&0.08\\2,4,6,3&2&0.17&2,4,6,5&3&0.08&3,5,6,1&3&0.08\end{array}\right]$

Read more about sampling distributions at:

brainly.com/question/10554762

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3 years ago

Jackie says that 200 ÷ 18 is he corrct

Dmitriy789 [7]

Answer:

11.1111111

Explanation:

3 0

3 years ago

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why is everyone on this app asking for help like just go get some help if you cant figure something out

Yuki888 [10]

Well actually some people use this app to double check their answers. If you don’t approve then you can leave- nobody is forcing you to be in here❤️

7 0

3 years ago

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Ariana is accelerating her car at a rate of 4. 6 m/s2 for 10 seconds. Her starting velocity was 0 m/s. What was her final veloci

Studentka2010 [4]

Answer:

<h3>the answer is v=46 m/s</h3>

Explanation:

<h3>to find the final velocity we use formula from uniformly accelerated motion , equation 1, that is ; V=U+at</h3>

<h3>our given is U=0m/s</h3><h2> a=4.6m/s^2</h2><h3> t=10s</h3><h3>requaired,V=?</h3>

<h3>solution will be; V = u+at</h3>

<h3>replacing the values of each individual</h3>

<h3>V=0m/s+(4.6m/s^2)(10s)</h3><h3>V=0m/s+46m/s ;second found on the unit of acceleration canceled by the unit of time and finaly the left is m/s</h3><h3>V=46m/s</h3>

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3 years ago

SITE in full sentence

drek231 [11]

Answer:

There is a site under work at that town. The site is a work in proggres.

Explanation:

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2 years ago

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