Hi,

$\dfrac{2c}{3}+1\ \textgreater \ 7\\\\3\times\left(\dfrac{2c}{3}+1\right)\ \textgreater \ 3\times7\\\\2c+3\ \textgreater \ 21\\2c\ \textgreater \ 21-3\\2c\ \textgreater \ 18\\\\c\ \textgreater \ \dfrac{18}{2}\\\\c\ \textgreater \ 9$

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3 years ago

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If a substance is transported across a cell membrane from an area of low concentration to an area of high concentration, you kno

Ronch [10]

It is a type of active transport because it will require energy to move against the concentration gradient (low to high)
- option A

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3 years ago

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